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3 years ago

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How far apart are two electrons if they exert a force of repulsion of 1.5 N on each other (The elementary charge is 1.6 x 10-19

C )?

1 answer:

MissTica3 years ago

5 0

Answer:

The distance between two charges i.e electrons with F= 1.5N is given by $r=1.232*10^{-14}$

Explanation:

To find the distance between 2 electrons, we'll use the Coulombs Law

Coulombs Law states the the Force of attraction or repulsion between any two chargers is directly proportional to the product of both charges and inversely proportional to the square of the distance between them.

Coulombs Law states that (when q₁ = q₂) :

$F=k\frac{q^2}{r^2}$

where

$k=8.9*10^9 Nm^2C^-2$

$q=1.6*10^{-19} C$

$F = 1.5 N$

Find r

$r^2=k\frac{q^2}{F}$

Substitute the values

$r^2=\frac{(8.9*10^9)(1.6*10^{-19})^2}{1.5}\\r^2= 1.5189*10^{-28}\\r=1.232*10^{-14}$

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How can you drop two eggs the fewest amount of times, without them breaking?

MrMuchimi

Answer:

Both eggs are identical. The aim is to find out the highest floor from which an egg will not break when dropped out of a window from that floor. If an egg is dropped and does not break, it is undamaged and can be dropped again. However, once an egg is broken, that's it for that egg.

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3 years ago

Now find the components NxNxN_x and NyNyN_y of N⃗ N→N_vec in the tilted coordinate system of Part B. Express your answer in term

MArishka [77]

Answer:

$N_{y} =Ncos$ Ф,

$N_{x} =-Nsin$ Ф

Explanation:

Now find the components NxNxN_x and NyNyN_y of N⃗ N→N_vec in the tilted coordinate system of Part B. Express your answer in terms of the length of the vector NNN and the angle θθtheta, with the components separated by a comma.

Vectors are quantities that have both magnitude and direction while scalar quantities have only magnitude but no direction.

This a vector quantity

from the diagram the horizontal component of the length of the vector will be

$N_{y} =Ncos$ Ф

the vertical component will be

$N_{x} =-Nsin$ Ф

this is in the opposite direction because the x can be extrapolated to the negative axis

7 0

3 years ago

Read 2 more answers

he calculation of kinetic energy uses the formula, KE = 1 2 mv2. Identify the unit that is required for mass and velocity, respe

Umnica [9.8K]

Mass is measured in kg
Velocity is measured in ms^-1
Hope this is what you were looking for

5 0

3 years ago

A uniform disk of mass M = 4.9 kg has a radius of 0.12 m and is pivoted so that it rotates freely about its axis. A string wrapp

AlekseyPX

Answer:

(A) 2.4 N-m

(B) $0.035kgm^2$

(C) 315.426 rad/sec

(D) 1741.13 J

(E) 725.481 rad

Explanation:

We have given mass of the disk m = 4.9 kg

Radius r = 0.12 m, that is distance = 0.12 m

Force F = 20 N

(a) Torque is equal to product of force and distance

So torque $\tau =Fr$ , here F is force and r is distance

So $\tau =20\times 0.12=2.4Nm$

(B) Moment of inertia is equal to $I=\frac{1}{2}mr^2$

So $I=\frac{1}{2}\times 4.9\times 0.12^2=0.035kgm^2$

Torque is equal to $\tau =I\alpha$

So angular acceleration $\alpha =\frac{\tau }{I}=\frac{2.4}{0.035}=68.571rad/sec^2$

(C) As the disk starts from rest

So initial angular speed $\omega _{0}=0rad/sec$

Time t = 4.6 sec

From first equation of motion we know that $\omega =\omega _0+\alpha t$

So $\omega =0+68.571\times 4.6=315.426rad/sec$

(D) Kinetic energy is equal to $KE=\frac{1}{2}I\omega ^2=\frac{1}{2}\times 0.035\times 315.426^2=1741.13J$

(E) From second equation of motion

$\Theta =\omega _0t+\frac{1}{2}\alpha t^2=0\times 4.6+\frac{1}{2}\times 68.571\times 4.6^2=725.481rad$

3 0

3 years ago

You charge an initially uncharged 89.9-mf capacitor through a 30.5-ω resistor by means of a 9.00-v battery having negligible int

blsea [12.9K]

<span>1) The differential equation that models the RC circuit is :

(d/dt)V_capacitor </span>+ (V_capacitor/RC) = (V_source/<span>RC)</span>

<span>Where the time constant of the circuit is defined by the product of R*C

Time constant = T = R*C = (</span>30.5 ohms) * (89.9-mf) = 2.742 s

2) C<span>harge of the capacitor 1.57 time constants

1.57*(2.742) = 4.3048 s

The solution of the differential equation is

</span>V_capac (t) = (V_capac(0) - V_capac(∞<span>))e ^(-t /T) +  </span>V_capac(∞)

Since the capacitor is initially uncharged V_capac(0) = 0

And the maximun Voltage the capacitor will have in this configuration is the voltage of the battery V_capac(∞) = 9V

This means,

V_capac (t) = (-9V)e ^(-t /T) + 9V

The charge in a capacitor is defined as Q = C*V

Where C is the capacitance and V is the Voltage across

V_capac (4.3048 s) = (-9V)e ^(-4.3048 s /T) + 9V

V_capac (4.3048 s) = (-9V)e ^(-4.3048 s /2.742 s) + 9V

V_capac (4.3048 s) = (-9V)e ^(-4.3048 s /2.742 s) + 9V = -1.87V +9V

V_capac (4.3048 s) = 7.1275 V

Q (4.3048 s)  = 89.9mF*(7.1275V) = 0.6407 C

3) The charge after a very long time refers to the maximum charge the capacitor will hold in this circuit. This occurs when the voltage accross its terminals is equal to the voltage of the battery = 9V

Q (∞)  = 89.9mF*(9V) = 0.8091 C

7 0

3 years ago