Answer:
0.1 m/s
Explanation:
Please see attached photo for explanation.
Mass of 1st cart (m₁) = 500 g
Initial velocity of 1st cart (u₁) = 0.25 m/s
Mass of 2nd cart (m₂) = 750 g
Initial velocity of 2nd cart (u₂) = 0 m/s
Velocity (v) after collision =.?
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(500 × 0.25) + (750 × 0) = v(500 + 750)
125 + 0 = v(1250)
125 = 1250v
Divide both side by 1250
v = 125 / 1250
v = 0.1 m/s
Thus, the two cart will move with a velocity of 0.1 m/s after collision.
The answer is apogee my dude
First the velocity drops to zero in 1.2 secs. In those seconds it went upwards for 7.2 m, then it went from 87.2 to 0m. x-x0=v0*t+1/2*g*t^2 ergo t=sqrt(2x/g) that is 4.1761 s. Finally the total time required is 5.3761 s
I found this on arxsiv.org: “The central force motion between two bodies about their center of mass can be reduced to an equivalent one body problem in terms of their reduced mass m and their relative radial distance r. ... The potential V (r) from which this force is derived is also a function of r alone, F = −VV, V ≡ V (r).”
Mark as BRAINLIEST?
the radiogenic heat produced by the radioactive decay of isotopes in the mantle and crust, and the primordial heat left over from the formation of the Earth.
