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olasank [31]
3 years ago
14

What’s the correct answer for this?

Mathematics
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

C

Step-by-step explanation:

If you try to close the triangle at the right towards the left so that it imposes on the larger triangle we would have;

HJ ~ PQ

JN ~ QN

HN ~ PN

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Help pls ...................................
barxatty [35]

Answer:

x=-6.3÷3=2.1

X=3×12=36

X=3÷1.2=2.5

X=-1.2×-0.3=0.36

4 0
3 years ago
Read 2 more answers
Divide 36xy-39y over 3y
Tcecarenko [31]
\dfrac{ 36xy-39y}{3} 

Factor \ out \ the \ common \ term \ 3y 

\dfrac{3y(12x-13)}{3} 

y(12x-13)

 
    Cancel \ 3
3 0
4 years ago
Read 2 more answers
Can somebody help me with this problem
kati45 [8]
First substitute y=5x+7 so that would turn into 5x+7=6x

Then, isolate/solve for x for 5x + 7 = 6x, in this problem x=7

Substitute x=7 into y=5x+7

y=42


x=7, y=42
(7,42)


6 0
3 years ago
Solve equation by using the quadratic formula.
adoni [48]
ANSWER IS C because I looked it up
3 0
3 years ago
How much of a radioactive kind of ruthenium will be left after 8 hours if you start with 3,888
ziro4ka [17]

Answer:

Step-by-step explanation:

As an example, iodine-131 is a radioisotope with a half-life of 8 days. It decays by beta particle emission into xenon-131. After eight days have passed, half of the atoms of any sample of iodine-131 will have decayed, and the sample will now be 50% iodine-131 and 50% xenon-131.

50 grams to 25 grams is one half-life. 25 grams to 12.5 grams is another half-life. So, for 50 grams to decay to 12.5 grams, two half-lives, which would take 36 days total, would need to pass. This means each half-life for element X is 18 days.

7 0
3 years ago
Read 2 more answers
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