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WINSTONCH [101]
4 years ago
8

A employer, who started a new business, has promised his employees a minimum starting wage of $3, with an increase of $2 every 4

years. Sketch a graph of wage as a function of time for 16 years. Assume the wages take effect at the beginning of the year where the change is made. (HINT: use a step function to represent the function.)

Mathematics
1 answer:
7nadin3 [17]4 years ago
8 0
This is a step function because it increases in "steps".  The wage stays constant for a 4 year period, then jumps by $2 instead of a steady increase.

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Associative property (again, of multiplication and addition) means that it doesn't matter how you solve an expression if the same operand is used and some numbers are grouped. For eg. 3 * (5 * 4) = (3 * 5) * 4.
4 0
3 years ago
Use the model to write the equivalent fraction. The colored pieces show parts of the whole.
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What is your question?

4 0
3 years ago
Help me with 16,17,18,and 19 please simpl
mixas84 [53]

Answer:

Ques 16)

We have to simplify the expression:

\dfrac{t^2}{t^2+3t-18}-(\dfrac{5t}{t^2+3t-18}-\dfrac{t-3}{t^2+3t-18})\\   \\=\dfrac{t^2}{t^2+3t-18}-(\dfrac{4t+3}{t^2+3t-18})\\  \\=\dfrac{t^2-4t-3}{t^2+3t+18}

Ques 17)

\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{2w^2-9w+4}{(2w^2+9w-5)(w^2-w-12)}\\  \\=\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{(2w-1)(w-4)}{(2w-1)(w+5)(w+3)(w-4)}\\\\=\dfrac{3w^2+7w-7}{(w+3)(w+5)}+\dfrac{1}{(w+3)(w+5)}\\\\=\dfrac{3w^2+7w-7+1}{(w+3)(w+5)}\\\\=\dfrac{(3w-2)(w+3)}{(w+5)(w+3)}\\\\=\dfrac{3w-2}{w+5}

Ques 18)

Let the blank space be denoted by the quantity 'x'.

\dfrac{x}{12a^2+8a}+\dfrac{15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\ \\\dfrac{x+15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a(3a+2)}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a}=7a\\\\x+15a^2=28a^2\\\\x=28a^2-15a^2\\\\x=13a^2

Ques 19)

Let the missing quantity be denoted by 'x'.

\dfrac{p^2+7p+2}{p^2+5p-14}-\dfrac{x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\ \\\dfrac{p^2+7p+2-x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\\\\dfrac{p^2+7p+2-x}{(p-2)(p+7)}=\dfrac{p-1}{p-2}\\\\p^2+7p+2-x=(p-1)(p+7)\\\\p^2+7p+2-x=p^2+6p-7\\\\x=p+9


7 0
3 years ago
The sum of the ages of ahsan and his mother is 61 years.The difference in their ages is 29 years.By forming a pair of simultaneo
Llana [10]

Answer:

(i). Ahsan's Present Age = 16

(ii). Age of Ahsan's Mother when ahsan is 21 years old = 50

Step-by-step explanation:

Let's say, x represents the age of ahsan.

y represents the age of his mother.

The system of equation from the date given is:

\begin{bmatrix}x+y=61\\ -x+y=29\end{bmatrix}

Solve them will get us:

x=16,\:y=45

Regards: Umer

8 0
3 years ago
1 each of the two items that Val bought cost more than 10$ 2. Val spent 34$ for the 2 items. 3. Neither of the two items that Va
DerKrebs [107]
Statement : Val spent $ 34 for the 2 items

contradiction : Neither of the 2 items that Val bought cost more then $ 15

think about it....if neither of them cost more then 15....lets say they cost 15 each...then there is no way he spent $ 34.....he would spend at most $ 30
8 0
3 years ago
Read 2 more answers
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