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2 years ago

9

Vassil rounded to the nearest half to estimate the product of Five-eighths and StartFraction 8 over 9 EndFraction. How do the es

timated and actual products compare?

2 answers:

Firdavs [7]2 years ago

5 0

Answer:

A

Step-by-step explanation:

cricket20 [7]2 years ago

4 0

Answer:

ITS A

Step-by-step explanation:

You might be interested in

20 business cards are placed in a hat, 10 belong to women, 10 belong yo men If 2 cards are drawn at once. what's the probability

erik [133]

Answer:

First choice:

$\large\boxed{\large\boxed{5/19}}$

Explanation:

<em>The probability that the first is a man's card and the second, a woman's card</em> is calculated as the product of both probabilities, taking into account the fact that the second time the number of cards in the hat has changed.

In spite of it is said that the cards are drawn at once, since it is stated a specific order for the cards (first is a man's card and the second, a woman's card) you can model the procedure as if the cards were drawn consecutively, instead of at once.

<u>1. Probability that the first is a man's card</u>

Number of cards in the hat = 20 (the 20 business card)

Number of man's card in the hat: 10

Probability = favorable oucomes / possible outcomes = 10/20 = 1/2.

<u />

<u>2. Probability that the second is a woman's card</u>

Number of cards in the hat = 19 (there is one less card in the hat)

Number of wonan's card in the hat: 10

Probability = favorable oucomes / possible outcomes = 10/19.

<u>3. Probability that the first is a man's card and the second, a woman's card</u>

<u />

(1/2) × (10/19) = 5/19

That is the first choice.

5 0

2 years ago

Read 2 more answers

ExtremeBDS [4]

Step 3 is the frist incorrect step it should be: 2x-3=3 or 2x-3=-3

3 0

3 years ago

Read 2 more answers

The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time

cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

$1\leq t\geq \sqrt{2}$

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

$h =20-5t^{2}$ -----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height $h = 15m$

Put height value in equation 1

$15 =20-5t^{2}$

$5t^{2} =20-15$

$5t^{2} =5$

$t^{2} =1$

$t =\pm1$

We know that the time is always positive, therefore $t=1$

when the stuntman is 10m above the ground.

height $h = 10m$

Put height value in equation 1

$10 =20-5t^{2}$

$5t^{2} =20-10$

$5t^{2} =10$

$t^{2} =\frac{10}{5}$

$t^{2} =2$

$t=\pm\sqrt{2}$

$t=\sqrt{2}$

Therefore ,time interval of camera film him is $1\leq t\geq \sqrt{2}$

7 0

3 years ago

3. Two linear functions are shown below. Which function has the greater rate of change? Justify your response LOOK AT PIC! plz h

Rainbow [258]

Answer:

Function B has the greater rate of change

Step-by-step explanation:

Function A has a slope of 1/3

Function B has a slope of 1/2

When comparing slopes, the higher value has the greater rate of change

1/2 > 1/3

7 0

3 years ago

Simultaneous equations<br> x^2+3xy=10<br> x=2y

satela [25.4K]

9514 1404 393

Answer:

(x, y) = (-2, -1) or (2, 1)

Step-by-step explanation:

Substitute for x in the first equation:

(2y)^2 +3(2y)y = 10

10y^2 = 10

y^2 = 1

y = ±1

x = 2y = ±2

Solutions are (x, y) = (-2, -1) or (2, 1).

8 0

2 years ago