Question

F the height of the parallelogram shown is decreased by 1 inch and the base is decreased by 2 inches, what is the area of the new parallelogram?
Parallelogram a
78 in2


b
84 in2


c
104 in2


d
108 in2

Answer 1

Answer:

The area of the new parallelogram is (bh - 2b - h + 2).

Step-by-step explanation:

The area of a parallelogram is:

$\text{Area}=\text{base}\times \text{height}$

Let the original base be denoted by, b and the original height be denoted by, h.

It is provided that the height of the parallelogram is decreased by 1 inch and the base is decreased by 2 inches.

The new base and height are:

b₁ = b - 1

h₁ = h - 2

The new area of the parallelogram is given by:

$\text{New Area}=b_{1}\times h_{1}\\\\=(b-1)(h-2)\\\\=bh-2b-h+2$

Thus, the area of the new parallelogram is (bh - 2b - h + 2).