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Nitella [24]
3 years ago
6

What is the mode? –244–2–44–2–2

Mathematics
1 answer:
vesna_86 [32]3 years ago
4 0

Answer:

mode is -2

Step-by-step explanation:

mode is the number that appears the most time in data set

in this case -2

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Step-by-step explanation:

  1. find the area of the base (square)=900 sq. cm
  2. find area of triangles=1260 sq. cm
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50 POINTS Which relation is a function of x?<br> Look at the picture
muminat

Answer:

The fourth one

Step-by-step explanation:

It has no repeating x's or y's

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2z -5(z +2) = -8 - 2z<br><br> Please explain!! Thank you
Korolek [52]

Follow PEMDAS.

You would first do your distributive property which is, -5(z+2). You would multiply -5 to z and -5 to 2 which will give you -5z + -10.

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Now you have the equation 2z-5z-18=-2z

Now combine like terms. 2z-5z= -3z

Now you have the equation -3z-18=-2z

Now you must move the -3z to the other side of the equal sign by adding the opposite which is +3z to -2z which will give you +1z

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3 years ago
From a height of 50 meters above sea level on a cliff, two ships are sighted due west. The angles of depression are 61° and 28°.
Olenka [21]

Answer:

The ships are 66 meters apart.

Step-by-step explanation:

For the sake of convenience, let us label ships A and B

As shown in the figure, the distances to the ships from right triangles.

The distance to the ship A is d_1 and it is given by

tan (61^o)= \dfrac{50}{d_1}

d_1=\dfrac{50}{tan (61^o)}

\boxed{d_1= 27.71m}

And the distance to the ship B is d_2 and is given by

tan (28^o)= \dfrac{50}{d_2}

d_2=\dfrac{50}{tan (28^o)}

\boxed{ d_2=94.04m}

Therefore, the distance d between the ships A and B is

d= d_2-d_1=94.04-27.7\\\\\boxed{d=66m}

In other words, the ships are 66 meters apart.

8 0
3 years ago
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I need help figuring this problem out. <br> -x÷1/2=?
Lesechka [4]
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