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alexira [117]
3 years ago
9

Write an equation in slope-intercept form of the line with slope 3/4 that contains the point (-4,1)

Mathematics
1 answer:
marusya05 [52]3 years ago
6 0

Answer:

y = 3/4x + 4

Step-by-step explanation:

to put it into slope intercept form, you need to find the y intercept or b becasue the slope intercept form is y = mx + b where b is the y intercetpt and m is the slope. To find b you insert the points you were given so 1 = -4(3/4) + b

which simplifies to 4 = b so then you can put in your slope and y intercept into slope intercept form

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5 x 8 /a*7

Step-by-step explanation:

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!!!!!!!please help!!!!!!!!
GuDViN [60]

Answer:

The first one is No. The second one I do not know unfortunately.

Step-by-step explanation:

I am in the middle of this lesson in my math class as well and I know that in order to make a triangle, you need the two smaller sides to add up to become larger than the biggest side. In the case of the first question, the two smaller sides, 6 and 3 equal 9, which is not bigger than the biggest side which is 10. I hope you can find the answer to the second one, but for now, the first one is No.

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3 years ago
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5 0
3 years ago
Read 2 more answers
B)the LCM of three numbers is 24 and their G.C.D is 4. If two<br>find the other number​
kicyunya [14]

6

Step-by-step explanation:

because 6*4=24, so the G.C.D is 4 and the other number is 6

4 0
3 years ago
The measure of angle A to the nearest tenth of a degree is: A 18.5 B 19.5 C 20.5
Andrew [12]

Answer:

B


Step-by-step explanation:

<u>This is a right triangle as shown by the right angle.</u>

  • The side opposite the right angle is the hypotenuse, which is 9.
  • The side opposite angle A is 3.

So we have the opposite of A and the hypotenuse.

The trigonometric ratio that relates opposite side to hypotenuse is SINE.

sin\theta=\frac{opposite}{hypotenuse}

Since, we need angle A, \theta is A, opposite side is 3, and hypotenuse is 9, we substitute:

sinA=\frac{3}{9}\\sinA=\frac{1}{3}

<em>To solve for the angle, we use our calculator and find the inverse sin of \frac{1}{3} :</em>

A=sin^{-1}(\frac{1}{3})\\A=19.47

<em>Rounding to nearest tenth of a degree:</em>

A=19.5

B is the right choice.

6 0
3 years ago
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