I believe the error she made was adding it or multipulcation
Answer and Step-by-step explanation:
Alright, so when creating any type of math problem, it is important to identify the parts of the problem and where they go. First, we need to start by putting the problem together. We will use one of the most common forms of equations of math, also known as the linear equation of <em>y=mx+b.</em>
So we have: S(w)=__x + __. S(w) is also equal to f(x), which is also equal to y. So: y= __x + __.
Let's start filling this equation in. So, because it says that she will <em>add 25 dollars each week</em>, The problem is addition. Also, the 25 dollars each week will represent the mx in this situation. Here's why:
The x in this can stand for the amount of week she added this 25 dollars to her account. So:
y= 25x + __.
Now, we can add the 150 to the problem because that is what she started with for this one-time deal. So now we have:
y= 25x + 150.
You can now where everything is represented, but we are not done. Let's change y and x back into S(w) and w like the question asks us to have. So:
S(w)= 25w + 150.
If you want to solve this question, just replace the number of weeks in place of all w's in the equation, like this: S(2)= 25(2) + 150.
I hope that this helps.
Jay’s elevation is at -20.
Talia’s elevation is at 20.
Answer: im not sure
Step-by-step explanation:
Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
