Answer: Total cost is $1.75
Explanation:
Since we have given that
Number of postcards bought by Doug's family= 7
Cost of each postcard including tax = $0.25
Total cost is given by
Now, we want to show this in number line :
On the number line put all the number with a difference of 0.25 and run the number line seven times and we get the answer.
Each step is of length 0.25 and there are 7 jumps to reach required answer.
So, after 7 jumps we reach at 1.75 which is the required answer.
Hence total cost is $1.75
ES is half of EF since a chord is bisected by the radius. ES = 10
Because we know the midpoint is in the middle, we know that both sides are equal.
So set both = to each other
4x - 1 = 3x + 3
add 1 to both sides
4x=3x+4
then subtract 3x from both sides and because there is always a 1 in front of x the answer would be
x=4
Answer:
45 degrees
Step-by-step explanation:
angle QRS is same as (2x + 3) because it is an isosceles triangle
so, 90 + (2x+3) + (2x+3) =180 degrees
2x+3 +2x+3=180-90
2x+2x +3+3=90
4x+6=90
4x=90-6
4x=84
x=84/4
x=21
substitute x=21 in (2x+3)
2*21+3=45
Answer:
Part A: impossible
Part B: Either equal or blue
Part C: 9 green and 2 blue were added
Step-by-step explanation:
Part A:
The only colors included in this problem are red, blue, and green. There is no black colored pencil, therefore, it is impossible to get one from the box.
Part B:
I'm not sure what you're asking in this question, but I will give you the two choices. If it is before the additional 11 colored pencils are added to the box, the chance of drawing a red and the chance of drawing a blue will be equal, because both of them have 11 of each color. If it is after the additional 11 colored pencils are added to the box, then the chance of drawing a blue colored pencil will be greater than the chance of drawing a red colored pencil. After the 11 colored pencils are added, there are 13 blue and 11 red. The blue is greater.
Part C:
The least number of green colored pencils added has to be 9, because the chance of drawing a green pencil is now greater than the chance of drawing a red pencil. If we add 8 more green pencils, the likelihood would be the same. Therefore, the number of green colored pencils added has to be at least 9. If we have the last 2 colored pencils be blue, then there would be 11 red, 13 blue, and 12 green. This fits all the conditions, therefore, adding 9 green colored pencils and 2 blue colored pencils is the answer.
I hope this helps and please mark me as brainliest!
