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3 years ago

HELP SO I DONT FAIL THIS YEAR

Mathematics

1 answer:

natita [175]3 years ago

5 0

Answer:

Option Z

The graph in the attached figure

Step-by-step explanation:

Let

x----> the number of chickens sandwiches

y----> the number of hamburgers

we know that

$x+y\leq 40$ ----> inequality A

$4x+2y\geq 100$ ----> inequality B

using a graphing tool

The solution is the triangular shaded area

see the attached figure

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The sum of two binomials is 5x^2-6x . If one of the binomials is3x^2-2x , what is the other binomial?

vlada-n [284]

Its 2x^2-4x, to check it add it to 3x^2-2x or
2x^(2)-4x+3x^(2)-2x

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4 years ago

A child’s wading pool has a diameter of 5 feet and a height of 2 feet. How much water would it take to fill the pool?

Svetradugi [14.3K]

Answer:

12.5π or ≈39.27

Step-by-step explanation:

The formula for finding the volume is V=πr^2*d (where h is the height and r is the radius).

Plug in the values: V=π(2.5)^2*2 (Diameter=2*Radius)

Solve: V=6.25π*2

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3 years ago

What is the volume of this prism? Enter your answer in the box.

jarptica [38.1K]

Short Answer: 560 cm squared

Long Answer:

You can get the volume of a rectangular prism by multiplying the height, width, and length together.

7 0

2 years ago

Please!!! Help!!! Brainliest of Right! it goes as 50 point in the end but i used 100 point if you help me i will help you!!

vekshin1

Answer:

2. 3.913 kg (3 dp)

3. light cream

4. 240 CoffeeStops

5. 7 CoffeeStops per square mile

6. 2,861 cups of coffee each day

Step-by-step explanation:

Given:

Skim milk density at 20 °C = 1.033 kg/l
Light cream density at 20 °C = 1.012 kg/l
1 liter = 0.264 gallons

Question 2

$\begin{aligned}\textsf{1 gallon} & = \sf \dfrac{1}{0.264}\:liters\\\\\implies \textsf{Mass (1 gallon of skim milk)} & = \sf Density \times Volume\\& = \sf 1.033\:kg/l \times \dfrac{1}{0.264}\:l\\& = \sf 3.913\:kg\:(3\:dp)\end{aligned}$

Therefore, the mass of 1 gallon of skim milk is 3.913 kg (3 dp)

---------------------------------------------------------------------------------------------

Question 3

Given:

Volume of liquid = 9 liters
Mass of liquid = 9.108 kg

$\begin{aligned}\implies \sf Density & = \sf \dfrac{Mass}{Volume}\\\\& = \sf \dfrac{9.108\:kg}{9\:l}\\\\& = \sf 1.012\:kg/l \end{alilgned}$

Therefore, the container holds light cream.

---------------------------------------------------------------------------------------------

Question 4

Given:

15 CoffeeStops per 100,000 people
Population of Manhattan ≈ 1,602,000 people

$\begin{aligned}\implies \textsf{Number of Coffeestops} & = \sf \dfrac{population}{density}\\\\& = \sf \dfrac{1,602,000}{100,000/15}\\\\& = \sf \dfrac{1,602,000}{100,000} \times 15\\\\& = \sf 240.3\end{aligned}$

Therefore, there are 240 CoffeeStops.

---------------------------------------------------------------------------------------------

Question 5

Given

Manhattan ≈ 34 square miles

$\begin{aligned}\implies \textsf{CoffeeStops density} & = \sf \dfrac{number\:of\:stores}{land\:area}\\\\& = \sf \dfrac{240}{34}\\\\& \approx \sf 7 \: \textsf{CoffeeStops per square mile}\end{aligned}$

Therefore, the density of CoffeeStops is 7 per square mile.

---------------------------------------------------------------------------------------------

Question 6

Given:

Each person buys 3 cups of coffee per week

$\begin{aligned}\implies \textsf{Cups served each week} & = \textsf{number of people} \times \textsf{number of cups per week}\\& = \sf 1,602,000 \times 3\\& = \sf 4,806,000\: \textsf{cups per week}\\\\\implies \textsf{Cups per day} & = \sf \dfrac{\textsf{cups per week}}{\textsf{days in a week}}\\\\& = \sf \dfrac{4,806,000}{7}\\\\& = \sf 686,571\:\textsf{(nearest whole number)}\end{aligned}$

$\begin{aligned}\implies \textsf{Cups served per day per shop} & = \dfrac{\textsf{cups per day}}{\textsf{number of shops}}\\\\& = \sf \dfrac{686,571}{240}\\\\& = \sf 2,861\: \textsf{(nearest whole number)} \end{aligned}$

Therefore, each Manhattan CoffeeStop serves approximately 2,861 cups of coffee each day.

7 0

2 years ago

a force of 2 pounds is needed to stretch a spring 8 inches.what force is required to stretch the spring 16 inches

Korvikt [17]

Answer:

Four (4) pounds

Step-by-step explanation:

Because we required two (2) pounds to stretch the spring eight (8) inches, we need double the force to stretch it sixteen (16) inches. Sixteen is just double the original amount, meaning we need four (4) pounds to stretch the spring sixteen inches.

Hope this helps!

5 0

3 years ago