Hello, There are endless expressions. Since, you multiply this fraction by a costant k / k
If k = 2
Then,
(5/9) = ( 5/9) × ( k / k)
= (5/9) × ( 2/2)
= (5 × 2 / 9×2)
= 10 / 18
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The only restriction for k is zero and the infinite. Because there is no "0/0" and "infinito/ infinito" at math.
Answer:
Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)
Problem 2) Runner B has the smallest period
Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.
Step-by-step explanation:
The frequency of the football player is 160 heartbeats per minute.
The period is (using the equation you showed above):
![Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds](https://tex.z-dn.net/?f=Period%20%3D%20%5Cfrac%7B1%7D%7Bfrequency%7D%20%3D%20%5Cfrac%7B1%7D%7B160%7D%20%5C%2Cminutes%3D%200.00625%5C%2C%5C%2Cminutes%20%3D%200.375%5C%2C%5C%2Cseconds)
second problem:
Runner A does 200 loops in 60 minutes so his frequency is:
loops per minute
then the period is: 0.3 minutes (does one loop in 0.3 minutes)
the other runner does 200 loops in 65 minutes, so his frequency is:
loops per minute
then the period is:
![\frac{13}{40} =0.325\,\,\,minutes](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B40%7D%20%3D0.325%5C%2C%5C%2C%5C%2Cminutes)
Therefore runner B has the smaller period
Answer:
y =
x - 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = ![\frac{y_{2}-y_{1} }{x_{2}-x_{1} }](https://tex.z-dn.net/?f=%5Cfrac%7By_%7B2%7D-y_%7B1%7D%20%20%7D%7Bx_%7B2%7D-x_%7B1%7D%20%20%7D)
with (x₁, y₁ = x- intercept (10, 0) and (x₂, y₂ ) = y- intercept (0, - 2)
m =
=
= ![\frac{1}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D)
The y- intercept c = - 2
y =
x - 2 ← equation of line
20096m.
Since the radius is 80, the formula is x²×3.14.
80²=6400
6400×3.14=20096
m is the unit
Answer: 20096 meters