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Marina86 [1]
3 years ago
11

Can someone please help mee. use transformations to solve the equation. 3 2/3x = 22

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0

1. Note that

3\dfrac{2}{3}=\dfrac{3\cdot 3+2}{3}=\dfrac{9+2}{3}=\dfrac{11}{3}.

2. Then the equation 3\dfrac{2}{3}x=22 can be rewritten

\dfrac{11}{3}x=22.

3. Solve it:

x=22:\dfrac{11}{3},\\ \\x=22\cdot \dfrac{3}{11}=2\cdot 3=6.

Answer: x=6

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olga2289 [7]

Answer:

data about a person's heartbeat, perspiration levels, respiration, and body movements.

Step-by-step explanation:

the answer to the question is that

biometric measures are useful for evaluating data like that of heartbeat, perspiration levels, respiration, body movements of a person.

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3 0
3 years ago
Theo ate .7 of his candy bar. How many more tenths must he eat to finish the whole candy bar?
Julli [10]

Answer:

3 tenths

Step-by-step explanation:

One candy bar

= 1 candy bar

= 1.0, or 10 tenths (one tenth is 0.1)

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8 0
2 years ago
Guys I really need help with these too thanks u before!!!!
Natali5045456 [20]
Hey!!

here is your answer >>>

1) 3x - 10 > 11

let's take this as 3x - 10 = 11

3x = 21

x = 7
So, The numbers of X are always more than 7

2) 9x + 2 < 5

9x + 2 = 5

9x = 3

x = 1÷2

The numbers of X are always less than 1 ÷ 2

3) 2x + 8 < 6

2x + 8 = 6

2x = 2

x = 1

The numbers of X are less than 1

4) 4x - 3 < 12

4x - 3 = 12

4x = 15

x = 15 ÷ 4

The numbers of X are less than 15 ÷ 4

5) 2 ( 9 + x ) > 20

2 ( 9 + x ) = 20

9 + x = 10

x = 1

The numbers of X are more than 1

We can solve the rest using this

Hope my answer helps!
5 0
3 years ago
F function g has the factors (x − 7) and (x + 6), what are the zeros of function g?
Allisa [31]

Answer:

Zeros are 7 and -6

4 0
3 years ago
A rectangle has an area of 20 ft.² in a similar rectangle has an area of 180 ft.² what is the ratio of areas of the similar
vovikov84 [41]
\bf \qquad \qquad \textit{ratio relations}&#10;\\\\&#10;\begin{array}{cccllll}&#10;&Sides&Area&Volume\\&#10;&-----&-----&-----\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}&#10;\end{array}\\\\&#10;-----------------------------\\\\

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s^2}{s^2}=\cfrac{20}{180}\implies \left( \cfrac{s}{s} \right)^2=\cfrac{20}{180}\implies \cfrac{s}{s}=\sqrt{\cfrac{20}{180}}&#10;\\\\\\&#10;\cfrac{s}{s}=\cfrac{\sqrt{20}}{\sqrt{180}}\implies \cfrac{s}{s}=\cfrac{2\sqrt{5}}{6\sqrt{5}}\implies \cfrac{s}{s}=\cfrac{2}{6}\implies \cfrac{s}{s}=\cfrac{1}{3}
6 0
3 years ago
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