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Vadim26 [7]
3 years ago
10

A convenience store sells two brands of orange juice. Brand A contains 8 fluid ounces and cost 1.28 Brand B contains 12 fluid ou

nces and cost 1.68 what is the difference in cost , in dollars , per fluid ounce between the two brands of juice ?

Mathematics
1 answer:
lapo4ka [179]3 years ago
7 0
Brand b is 2 cents cheaper than brand a because it is 14 cents per ounce and brand a is 16 cents per ounce you do 1.68 divided by 12 and 1.28 divided by 8
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Answer:

A) 12.1 , 12.01

B) infinitely large

Step-by-step explanation:

Give that the function f(x)=x2 describes the area of the square, f(x), in square inches, whose sides each measure x inches. If x is changing. 

Using the formula

(f(a + h) - f(a))/h

as x changes from 6 inches to 6.1 inches

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= 12.01

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Read 2 more answers
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0
3 years ago
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