Z>7 I think that’s the answer let me know if it’s right or not
Answer:
2/1 or 2
Step-by-step explanation:
5/49(x)<span> = 20/7
5x/49 = 20/7
</span>5x/49 × 49 = 20/7 <span>× 49
</span>5x = 140
5x / 5 <span> = 140 / 5
</span>x = 28
Answer:
the first problem is - 85 and you continue from there
We have the price of a senior ticket is $4 and the price of a child ticket is $7
Step-by-step explanation:
We can form two equations, let the price of a senior ticket be s and the price of a child ticket be c.
We have from day 1:
A: 3s + 9c = 75
And from day 2:
B: 8s + 5c = 67
Now we can rewrite A as:
A: 24s + 72c = 600
And can rewrite B as:
B: 24s + 15c = 201
Now A-B can be written as:
A-B: 57c = 399
So c = 7
Now substituting this back into A we get:
A: 3s + 63 = 75
A: 3s = 12
So s = 4
We have the price of a senior ticket is $4 and the price of a child ticket is $7
Let x be the amount invested at 6%
840 = 0.06x + 0.075(2x)
840 = 0.06x + 0.15x
840 = 0.21x
x = 840/0.21
x = 4000
Therefore, she invests $4000 at 6% and $8000 at 7.5%