Yes you have the correct answers for each of the four problems. Nice work.
For anyone curious,
rd = removable discontinuity
id = infinite discontinuity
c = continuous
Answer:
41.29 cm²
Step-by-step explanation:
From the question,
Area of the shaded portion = Area of the circle - area of the square.
A' = πr²-L²...… Equation 1
Where A' = Area of the shade portion, r = radius of the circle, L = length of the square, π = pie
Given: r = 4 cm, L = 3 cm
Constant: π = 22/7.
Substitute these values into equation 1
A' = [(22/7)×4²]-3²
A' = 50.29-9
A' = 41.29 cm²
Hence the area of the shaded portion is 41.29 cm²
Set each set of parentheses to 0 and solve for x.
X—6 = 0
X = 6
X + 5 = 0
X = -5
X-9 = 0
X = 9
The zeros are 6, -5, 9
