Part I


part II

now, the form above is the point-slope form, and that'd be the equation, you can leave it like so, or you can solve for "y", and put it in slope-intercept, same equation though.
Answer
given,
mean = 12 Kg
standard deviation = 0.5 Kg
assume the observed statistic is = 11.1
now, 
assuming the number of sample = 4
n = 4
Hypothesis test:
H₀ : μ≥ 12
Ha : μ < 12
now,
significant level α = 0.05


z* = -3.60
Test statistics, Z* = -3.60
P-value
P(Z<-3.60) = 0.002 (from z- table)
P- value = 0.002
now,
reject the value of H₀ when P-value < α
0.002 < 0.05
since, it is less P-value < α , we have to reject the null hypothesis
Answer:
40 students
Explanation:
So its 45% out of 100%. multiply 18 by 100% and divide it by 45 and you get 40
Answer:
3x -2y = -14
Step-by-step explanation:
The parallel line will have a new constant that can be found by substituting the given point for x and y.
-3x +2y = -3(0) +2(7) = 14
An equation for the parallel line is ...
-3x +2y = 14
__
In standard form, the leading coefficient is positive, so the standard form equation is ...
3x -2y = -14
Answer: 0.26
Step-by-step explanation:
As per given , we have
P(green tail) = 0.36
P(red fins) = 0.59
P(both a green tail and red fins ) = 0.21
Now, P(Neither red fin nor green tail )= 1 - P(either red fin or green tail )
<em>[P(neither A nor B)= 1- P(either A or B)]</em>
= 1-(P(green tail) +P(red fins)+P(both a green tail and red fins ))
<em>[P(A or B)= P(A)+P(B)-P(A and B)]</em>
= 1- (0.36+0.59-0.21)
= 1-(0.74)
= 0.26
Hence, the probability that the selected fish will not have a red fin or a green tail = 0.26