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Fiesta28 [93]
3 years ago
5

Find the value of x to make the following expression true. 3x=729

Mathematics
2 answers:
Zolol [24]3 years ago
8 0

Answer: x=243

Step-by-step explanation: Long division, 729 divided by 3

ohaa [14]3 years ago
6 0
The value of x is 243
(correct me if wrong)
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What is the value of y if f||n<br> ?????
Elenna [48]

Answer:

y = 148°

Step-by-step explanation:

4x - 18 = 2x + 12 (alternate exterior angles are congruent)

Collect like terms

4x - 18 = 2x + 12

4x - 2x = 18 + 12

2x = 20

Divide both sides by 2

x = 10

y = 180 - (2x + 12) (linear pair theorem)

Plug in the value of x

y = 180 - (2(10) + 12)

y = 180 - (20 + 12)

y = 148°

5 0
3 years ago
A grocery sells green apples and red apples. On Monday, the store put 500 of each kind of apple on display. That day, the store
sergij07 [2.7K]

Answer:

342 red apples

Step-by-step explanation:

42+87+29=158

500-158=342

4 0
3 years ago
Read 2 more answers
A truck is carrying pear juice, pineapple juice, and grapefruit juice bottles in a ratio of
sweet [91]

Answer:

120

Step-by-step explanation:

We let N be such that

9N = number pear juice bottles,

1N = number of pineapple juice bottles,

2N = number of grapefruit juice bottles.

Then, 20 = 2N, so that N = 10, and

The total number of juice bottles =

9N+1N+2N =

9(10)+1(10)+2(10)=

90+10+20=120

 

6 0
2 years ago
3[(15 - 3) squared divided by 4]
Ronch [10]
<span>3[(15 - 3) squared divided by 4]
=</span><span>3[(15 - 3)^2 / 4]
=3</span>[(12)^2 / 4]
=3[144 / 4]
=3[36]
=108
8 0
3 years ago
Let Y1 and Y2 have the joint probability density function given by:
Ann [662]

Answer:

a) k=6

b) P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

Step-by-step explanation:

a) if

f (y1, y2) = k(1 − y2), 0 ≤ y1 ≤ y2 ≤ 1,  0, elsewhere

for f to be a probability density function , has to comply with the requirement that the sum of the probability of all the posible states is 1 , then

P(all possible values) = ∫∫f (y1, y2) dy1*dy2 = 1

then integrated between

y1 ≤ y2 ≤ 1 and 0 ≤ y1 ≤ 1

∫∫f (y1, y2) dy1*dy2 =  ∫∫k(1 − y2) dy1*dy2 = k  ∫ [(1-1²/2)- (y1-y1²/2)] dy1 = k  ∫ (1/2-y1+y1²/2) dy1) = k[ (1/2* 1 - 1²/2 +1/2*1³/3)-  (1/2* 0 - 0²/2 +1/2*0³/3)] = k*(1/6)

then

k/6 = 1 → k=6

b)

P(Y1 ≤ 3/4, Y2 ≥ 1/2) = P (0 ≤Y1 ≤ 3/4, 1/2 ≤Y2 ≤ 1) = p

then

p = ∫∫f (y1, y2) dy1*dy2 = 6*∫∫(1 − y2) dy1*dy2 = 6*∫(1 − y2) *dy2 ∫dy1 =

6*[(1-1²/2)-((1/2) - (1/2)²/2)]*[3/4-0] = 6*(1/8)*(3/4)=  9/16

therefore

P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

8 0
3 years ago
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