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kakasveta [241]
3 years ago
14

A triangular pyramid has a right triangle for its base. The perpendicular sides of the triangle are 10 inches and 18 inches long

.
Compute the volume of the triangular pyramid if the height is 14 inches.
Mathematics
1 answer:
igor_vitrenko [27]3 years ago
6 0
The formula for a triangular pyramid is 1/3AH. A is the area of the base. H is the height of the pyramid. So to find the area of a right triangle, you would use the formula (a x b)/2. So (10 x18)/2 is 90 inches^2. Now you can fill in the first formula. 1/3(90 x 14), which equals 420 inches^3. I hope you find this helpful (if correct.)
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Hope this helps! :)
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What is the side length of a cube that has a volume of 0.008 m
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8 0
3 years ago
Two more than eleven times a number is equal to 24. What is the number?
Luden [163]

Answer:

2

Step-by-step explanation:

24/ 11 = 2 2/11

so, we have 2 and 2/11

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6 0
3 years ago
Whitney drinks 1.5liters of water each day what is the total of liquid in liters does Whitney drink each day?
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4 0
3 years ago
Read 2 more answers
Historically 80% of the monitors made by your company will pass your stringent quality control checks. 40 monitors have just com
madam [21]

Answer:

a) 10.75% probability that exactly 30 of them will pass the quality control checks.

b) Expected value is 32

Variance is 6.4

Step-by-step explanation:

For each monitor, there are only two possible outcomes. Either they will pass the quality checks, or they will not pass these checks. The probability of a monitor passing these checks is independent of other monitors. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The variance of the binomial distribution is:

V(X) = np(1-p)

80% of the monitors made by your company will pass your stringent quality control checks.

This means that p = 0.8

40 monitors have just come off the assembly line.

This means that n = 40

a) What is the probability that exactly 30 of them will pass the quality control checks?

This is P(X = 30). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 30) = C_{40,30}.(0.8)^{30}.(0.2)^{10} = 0.1075

10.75% probability that exactly 30 of them will pass the quality control checks.

b) What are the expected value and variance of the number of these monitors that will pass the quality control checks?

E(X) = np = 40*0.8 = 32

Expected value is 32

V(X) = np(1-p) = 40*0.8*0.2 = 6.4

Variance is 6.4

4 0
3 years ago
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