Answer:
61.7% of container A is empty after the pumping is complete.
Step-by-step explanation:
The volume of a cylinder is calculated by the formula B×h, where B is the area of the base, or radius²×π.
The volume of cylinder A is 9²×π×10=810π.
The volume of cylinder B is 5²×π×20=500π.
The percent that will be used to fill container B is the complete volume of B out of A: ≈.61728395 which is 61.7% rounded to the nearest tenth.
The first and 3rd one down are correct. <<<<===== answer.
Answer:
x = 9,-21
Step-by-step explanation:
Given:
Transport -7 to add 8:
Cancel absolute sign and add plus-minus to 15:
Transport 6 to subtract ±15:
Consider:
or
or
Solution:
or
__________________________________________________________
Second Method
Given:
Transport -7 to add 8:
Absolute Function Property:
Consider both intervals:
When x ≥ a then:
Transport 6 to subtract 15:
When x < a then:
Transport -6 to add 15:
Transport negative sign to 21:
Solution:
or
__________________________________________________________
Let me know if you have any questions regarding this question, my answer or explanation. Hope this answer and explanation helps you and good luck with your assignment!
T<=5 is the equation
(the <= is a less than or equal to sign.)
The above formulas do not hold for r = 1. For r = 1, the sum of n terms of the Geometric Progression is Sn
n
= na.
(ii)When the numerical value of r is less than 1 (i.e., - 1 < r < 1), then the formula Sn
n
= a(1−rn)(1−r)
(
1
−
r
n
)
(
1
−
r
)
is used.
(iii) When the numerical value of r is greater than 1 (i.e., r > 1 or, r < -1) then the formula Sn
n
= a(rn−1)(r−1)
(
r
n
−
1
)
(
r
−
1
)
is used.
(iv) When r = 1, then Sn
n
= a + a + a + a + a + .................... to n terms = na.
(v) If l is the last term of the Geometric Progression, then l = arn−1
n
−
1
.
Therefore, Sn
n
= a(1−rn1−r
1
−
r
n
1
−
r
) = (a−arn1−r
a
−
a
r
n
1
−
r
) = a−(arn−1)r(1−r)
a
−
(
a
r
n
−
1
)
r
(
1
−
r
)
= a−lr1−r
a
−
l
r
1
−
r
Thus, Sn
n
= a−lr1−r
a
−
l
r
1
−
r
Or, Sn
n
= lr−ar−1
l
r
−
a
r
−
1
, r ≠ 1.