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Makovka662 [10]
3 years ago
12

Answer number 61 please

Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0
This is the depend grade but we do it adding all the numbers it might be B Or D
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Work out the surface area of this solid prism.
alexandr1967 [171]

Answer:

2520cm²

Step-by-step explanation:

Surface area = sum of the area of all the bases.

Area of bottom base = 28 * 30 = 840

Area of right base = 25 * 30 = 750

Area of left base = 17 * 30 = 510

Area of two triangles = ( 15 * 28 ) / 2 = 210 * 2 = 420

Then add all the areas together to find surface area

Surface area = 840 + 750 + 510 + 420 = 2520cm²

Relevant Formulas:

Area of a rectangle = length * width. This formula was used to find the area of the bottom base, the right base and the left base

Area of a triangle = ( height * base length ) / 2 . This formula was used to find the area of the sides which are triangles.

5 0
3 years ago
Shana bought sodas and popcorn for the movies. Sodas cost $3 each and popcorn cost $4 per bag. Shana bought 7 things from the co
erma4kov [3.2K]
Equation : 3s + 4p = $26
Answer : 2 sodas and 5 bags of popcorn.
The equation would be 3s + 4p = $26. 3s is the $3 for every soda and 4p is $4 for every bag of popcorn.
Shana bought 2 sodas and 5 bags of popcorn. 3 x 2 is 6 and 5 x 4 is 20 which would equal $26. They also equal to the 7 things because of the 2 sodas and 5 bags.
6 0
3 years ago
2.5 x 2.5 x 2.5 - 1.4 x 1.4 x 1.4<br>(2.5)2+ 2.5 X 1.4 + (1.4)2​
melomori [17]

Answer:

a) 2.5×2.5×2.5-1.4×1.4×1.4=12.881

b) (2.5)2+2.5×1.4+(1.4)2=31.5

Step-by-step explanation:

yuh multiple 2.5 three times and subtract 1.4 multiple three times. 2.5×2.5×2.5-1.4×1.4×1.4

15.625-2.744=12.881.

b) when opening bracket Yuh multiple the number in the bracket by the number outside the bracket. when bracket is open Yuh can now add, multiple to obtain your answer please

(2.5)2+2.5×1.4+(1.4)2

5+2.5×1.4+2.8

7.5×4.2=31.5

8 0
3 years ago
Kendal bought x boxes of cookies to bring to a party. Each box contains 12 2 points
valina [46]

9514 1404 393

Answer:

  • y = 12x +24
  • 744

Step-by-step explanation:

If there are x boxes, each containing 12 cookies, then the number of cookies in the boxes is 12x. If there are 24 more cookies than that at the party, we have ...

  y = 12x +24 . . . . . equation modeling party cookies

__

For x=60, the number of cookies at the party is ...

  y = 12·60 +24 = 720 +24

  y = 744 . . . cookies at the party

7 0
3 years ago
Kim and Danielle each improved their yards by planting hostas and ivy. They bought their supplies from the same store. Kim spent
svetlana [45]

Answer:

The cost of one hosta is $6

Step-by-step explanation:

A system of linear equations is a set of two or more equations of the first degree, in which two or more unknowns are related.

Solving a system of equations consists of finding the value of each unknown so that all the equations of the system are satisfied.

In this case, the variables are:

  • x = price of a hosta .
  • y = price of a pot of ivy.

If Kim spent $62 on 5 hostas and 4 pots of ivy, t his is represented by the equation: 5*x +4*y= 62

If Danielle spent $144 on 8 hostas and 12 pots of ivy, t his is represented by the equation: 8*x +12*y=144

So, the system of equations to solve is:

\left \{ {{5*x+4*y=62} \atop {8*x+12*y=144}} \right.

One way to solve a system of equations is through the substitution method, which consists of solving or isolating one of the unknowns (for example, x) and substituting its expression in the other equation. In this way, you obtain an equation of the first degree with the other unknown, and. Once solved, you calculate the value of x by substituting the already known value of y.

Isolating y from the first equation:

y=\frac{62-5*x}{4}

and replacing this expression in the second equation you get:

8*x +12*\frac{62-5*x}{4}=144

Solving:

8*x +\frac{12}{4}*(62-5*x)=144

8*x + 3*(62-5*x)=144

8*x + 3*62 - 3*5*x=144

8*x + 186 - 15*x=144

8*x  - 15*x=144 -186

(-7)*x= -42

x= (-42)÷ (-7)

x= 6

<u><em>The cost of one hosta is $6</em></u>

8 0
3 years ago
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