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Naddika [18.5K]
3 years ago
14

Select the correct values in the table.

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0
So if it can vary by 75 or less, the least it can be is 1,125 and the greatest it can be is 1275.
Therefore it must be between or equal to these two.

The answers are:
1,125
And
1,260
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ASAP ILL GIVE BRAINLIEST IF UR RIGHT!!! The radius of the cone is 5 in and y = 13 in. What is the volume of the cone in terms of
Blababa [14]

Answer: V = 100\pi in^{3} (third option)

Given Information:

  • V = \frac{1}{3}\pi r^{2} h <-- volume formula.
  • r = 5
  • y = 13
  • <em>h = ?</em>

To find h...

  • h, r, and y make a right triangle.
  • h and r are the two legs, y is the hyptenuse.
  • h^{2} + r^{2} = y^{2}
  • h^{2} + 5^{2} = 13^{2}
  • h^{2} + 25 = 169
  • h^{2} = 144
  • h = 12

Use formula:

  • V = \frac{1}{3}\pi r^{2} h
  • V = \frac{1}{3} \pi (5)^{2} (12)
  • V = \frac{1}{3} \pi (25)(12)
  • V = \frac{1}{3} \pi (300)
  • V = 100\pi
7 0
3 years ago
Read 2 more answers
Ummm what this ?? Helping my sister
Radda [10]

Answer:

ok this the answer   By definition, a rectangle is a parallelogram because its pairs of opposite sides are parallel. A rectangle also has the special characteristic that all of its angles are right angles; all four of its angles are congruent. The other special case of a parallelogram is a special type of rectangle, a square.

Step-by-step explanation:

6 0
3 years ago
Find the probability of getting four consecutive aces when four cards are drawn without replacement from a standard deck of 52 p
posledela

Answer:

<em>P=0.0000037</em>

<em>P=0.00037%</em>

Step-by-step explanation:

<u>Probability</u>

A standard deck of 52 playing cards has 4 aces.

The probability of getting one of those aces is

\displaystyle \frac{4}{52}=\frac{1}{13}

Now we got an ace, there are 3 more aces out of 51 cards.

The probability of getting one of those aces is

\displaystyle \frac{3}{51}=\frac{1}{17}

Now we have 2 aces out of 50 cards.

The probability of getting one of those aces is

\displaystyle \frac{2}{50}=\frac{1}{25}

Finally, the probability of getting the remaining ace out of the 49 cards is:

\displaystyle \frac{1}{49}

The probability of getting the four consecutive aces is the product of the above-calculated probabilities:

\displaystyle P= \frac{1}{13}\cdot\frac{1}{17}\cdot\frac{1}{27}\cdot\frac{1}{49}

\displaystyle P= \frac{1}{270,725}

P=0.0000037

P=0.00037%

3 0
3 years ago
Event A has a 0.3 probability of occuring and event B has a 0.4 probability of occuring. A and B are independent events. What is
GarryVolchara [31]
When you say either, you add both A and B
0.3+0.4=0.7
Your answer is 0.70 which means 70%
4 0
3 years ago
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Identify the pattern then write the next three terms in each sequence 192,96,48,24,...
Karo-lina-s [1.5K]
1st. Find the pattern
Pattern is dividing by 2.
24/2=12
12/2=6
6/2=3
4 0
3 years ago
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