Find the variance of the set of data to the nearest tenth: 5, 8, 2, 9, 4
1 answer:
Answer:
Therefore the variance on the data set is 8.3
Step-by-step explanation:
In order to find the variance of the set of data we first need to calculate the mean of the set, which is given by:
mean = sum of each element / number of elements
mean = (5 + 8 + 2 + 9 + 4)/5 = 5.6
We can now find the variance by applying the following formula:
So applying the data from the problem we have:
s² = [(5 - 5.6)² + (8 - 5.6)² + (2 - 5.6)² + (9 - 5.6)² + (4 - 5.6)²]/(5 - 1)
s² = [(-0.6)² + (2.4)² + (-3.6)² + (3.4)² + (-1.6)²]/4
s² = [0.36 + 5.76 + 12.96 + 11.56 + 2.56]/4 = 8.3
Therefore the variance on the data set is 8.3
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<h3>Answer: 80 degrees</h3>
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Explanation:
I'm assuming that segments AD and CD are tangents to the circle.
We'll need to add a point E at the center of the circle. Inscribed angle ABC subtends the minor arc AC, and this minor arc has the central angle AEC.
By the inscribed angle theorem, inscribed angle ABC = 50 doubles to 2*50 = 100 which is the measure of arc AC and also central angle AEC.
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Focus on quadrilateral DAEC. In other words, ignore point B and any segments connected to this point.
Since AD and CD are tangents, this makes the radii EA and EC to be perpendicular to the tangent segments. So angles A and C are 90 degrees each for quadrilateral DAEC.
We just found angle AEC = 100 at the conclusion of the last section. So this is angle E of quadrilateral DAEC.
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Here's what we have so far for quadrilateral DAEC
- angle A = 90
- angle E = 100
- angle C = 90
- angle D = unknown
Now we'll use the idea that all four angles of any quadrilateral always add to 360 degrees
A+E+C+D = 360
90+100+90+D = 360
D+280 = 360
D = 360-280
D = 80
Or a shortcut you can take is to realize that angles E and D are supplementary
E+D = 180
100+D = 180
D = 180-100
D = 80
This only works if AD and CD are tangents.
Side note: you can use the hypotenuse leg (HL) theorem to prove that triangle EAD is congruent to triangle ECD; consequently it means that AD = CD.