Answer:
step 1: move the -4 to the right: x^2 -2x = 4
step 2: add 1 to each side: x^2 -2x + 1 = 4 + 1
step 3: factor the left side and simplify the right side: (x-1)^2 = 5
step 4: take the square root of each side: x - 1 = sqr root of 5
step 5: move the 1 to the other side: and
Answer:
a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)
Step-by-step explanation:
Let's solve by separating variables:
a) x’=t–sin(t), x(0)=1
Apply integral both sides:
where k is a constant due to integration. With x(0)=1, substitute:
Finally:
b) x’+2x=4; x(0)=5
Completing the integral:
Solving the operator:
Using algebra, it becomes explicit:
With x(0)=5, substitute:
Finally:
c) x’’+4x=0; x(0)=0; x’(0)=1
Let be the solution for the equation, then:
Substituting these equations in <em>c)</em>
This becomes the solution <em>m=α±βi</em> where <em>α=0</em> and <em>β=2</em>
Where <em>A</em> and <em>B</em> are constants. With x(0)=0; x’(0)=1:
Finally: