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Helga [31]
3 years ago
6

Square corner is another name for

Mathematics
2 answers:
Nastasia [14]3 years ago
6 0
The other name for a square corner is a vertex
daser333 [38]3 years ago
5 0
Another name for a square corner is Vertex
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3 (n - 5) - (6 -2n) = 4n
Afina-wow [57]

Answer:

21

Step-by-step explanation:

3n - 15 - 6 + 2n = 4n

3 n + 2n = 4n + 15 + 6

5 n - 4n = 15 + 6

n = 21

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3 years ago
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A Circus charges two dollars and 50 Cent for kids tickets and six dollars for adults tickets. Last weekend, twice as many kids a
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Answer: The answer is 2,860.

Step-by-step explanation:

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Question 15 of 46
kifflom [539]

The given polynomial function has 1 relative minimum and 1 relative maximum.

<h3>What are the relative minimum and relative maximum?</h3>
  • The relative minimum is the point on the graph where the y-coordinate has the minimum value.
  • The relative maximum is the point on the graph where the y-coordinate has the maximum value.
  • To determine the maximum and the minimum values of a function, the given function is derivated(since the maximum or minimum is obtained at slope = 0)

<h3>Calculation:</h3>

The given function is

f(x) = 2x³ - 2x² + 1

derivating the above function,

f'(x) = 6x² - 4x

At slope = 0, f'(x) = 0 (for maximum and minimum values)

⇒ 6x² - 4x = 0

⇒ 2x(3x - 2) = 0

2x = 0 or 3x - 2 = 0

∴ x = 0 or x = 2/3

Then the y-coordinates are calculated by substituting these x values in the given function,

when x = 0;

f(0) = 2(0)³ - 2(0)² + 1 = 1

So, the point is (0, 1)

when x = 2/3;

f(2/3) = 2(2/3)³ - 2(2/3)² + 1 = 19/27

So, the point is (2/3, 19/27)

Since y = 1 is the largest value, the point (0, 1) is the relative maximum for the given function.

So, y = 19/27 is the smallest value, the point (2/3, 19/27) is the relative minimum for the given function.

Thus, option A is correct.

Learn more about the relative minimum and maximum here:

brainly.com/question/9839310

#SPJ1

3 0
2 years ago
What is 3√125x^12<br><br> A) 5x^2<br> B) 5x^4<br> C) 25x^2<br> D) 25x^4
Schach [20]
\sqrt[3]{125x^{12}}=\sqrt[3]{125}\cdot\sqrt[3]{x^{4\cdot3}}=5\sqrt[3]{(x^4)^3}=5x^4\\\\\text{Answer:}\ B)\ 5x^4\\\\\text{Used:}\\\sqrt[n]{a\cdot b}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\\\(a^n)^m=a^{n\cdot m}\\\\\sqrt[n]{a^n}=a
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3 years ago
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