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Serga [27]
3 years ago
8

Calculate the area of a regular hendecagon with a side length of 4 meters.

Mathematics
2 answers:
kaheart [24]3 years ago
6 0

Answer:option A is the correct answer.

Step-by-step explanation:

A hendecagon is a polygon with eleven sides. Therefore, a regular hendecagon has 11 equal sides and eleven equal angles.

The formula for determining the area of a hendecagon is expressed as

Area = 11/4 × Cot(π/11) × s^2

Where

s represents the side length of the hendecagon.

From the given information,

s = 4 meters

2π = 360 degrees

π = 360/2 = 180 degrees.

Therefore,

Area = 11/4 × Cot(180/11) × 4^2

Area = 11/4 × Cot(16.363636) × 4^2

Area = 11/4 × 3.4057 × 16

Area = 149.85m^2

BartSMP [9]3 years ago
6 0

Answer:

1288m2

Step-by-step explanation:

A= 1/2aP

Where: a is apothem; perpendicular distance from the center of polygon to one of the sides

and p is the perimeter

When you drop the perpendicular distance, it will bisect the side into two, which the form number of triangles.

4m/2=2m and form the right angle

Using the angle rule: SOHCATOA

Angle side:360/11=32.72

One side length=4tan32.72

14.64m then multiplying by 2=29.27, hence the perimeter is given by

29.72x11=322

A=1/2x4x322

A=1288m2

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2 years ago
The cylinder below has a volume of 536.94 cubic inches. What is the radius of the cylinder? (Use 3.14 for π.)
Anestetic [448]

We have been given volume of the cylinder which is 536.94 cubic inches. Now question says to find the radius of the cylinder.

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Now plug the value of volume and height in above formula

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3 0
3 years ago
This is how you do it
WITCHER [35]
Where's the full question
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3 years ago
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