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oksano4ka [1.4K]
3 years ago
13

If g(x)=x^2+4x-5, find g(-4) PLEASE HELP

Mathematics
1 answer:
lana [24]3 years ago
7 0

Answer:

-5

Step-by-step explanation:

g(x)=x^2+4x-5

g(-4)=(-4)^2+4(-4)-5

g(-4)=(-4)(-4)+(-16)-5

g(-4)=16-16-5

g(-4)=0-5

g(-4)=-5

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3 years ago
anyone know the answer i worked it out but didn't know where i messed up so i am just gonna ask for someone to help me with it.
hram777 [196]
I also worked it out but I got -5/3

2(6p-5) ≥ 3(p-8) -1

12p-10 ≥ 3p-24-1

12p-10 ≥ 3p-25

12p-3p ≥ -25+10

9p ≥ -15

-15/9

P ≥ -5/3
5 0
3 years ago
When rounded, what is the value of the 6 in 4.769
levacccp [35]
If u round tha to the nearest 10th it’s 4.8
7 0
3 years ago
6.15 divided by 31 rounded
nikdorinn [45]
It would be (rounded) 5
Because
31 / 6.15 = 5.04065

Hope this helped

Have a great day/night
7 0
3 years ago
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