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My name is Ann [436]
3 years ago
15

5. 6(2+ y)=3(3- y) Help

Mathematics
1 answer:
Maurinko [17]3 years ago
4 0

Answer:

Step-by-step explanation:

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A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms . The ball's height h (in meters) af
Alecsey [184]

A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms

Balls height h= 2 +9t -5t^2

To find all values of t for which the ball's height is 3 meters

We plug in 3 for h and solve for t

h= 2 +9t -5t^2

3 = 2 +9t -5t^2

Solve for t

0= -1+ 9t -5t^2

5t^2 - 9t + 1 = 0

Solve using quadratic formula

t= \frac{-b+- \sqrt{b^2-4ac} }{2a}

t= \frac{9+- \sqrt{(-9)^2-4*5*1} }{2*5}

After simplifying this,

t= \frac{9+\sqrt{61}}{10} = 0.11898

t= \frac{9-\sqrt{61}}{10} = 1.68102

the values of t for which the ball's height is 3 meters= 0.12 sec , 1.68 sec

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3 years ago
Regroup through thousands is the topic<br> Question: 25 tens = _____hundreds 5 tens?
kompoz [17]
<span>25 tens = __2___hundreds 5 tens

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3 years ago
Geometry: Write a formal proof, ASAP!!!
yulyashka [42]

{\qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

As we can see in the figure, lines m and n are parallel to each other. so we can apply Angle pair properties ~

So,

\qquad \sf  \dashrightarrow \:  \angle1  \cong \angle2

[ they form corresponding angle pair ]

and it's given that :

\qquad \sf  \dashrightarrow \:  \angle2 \cong\angle 3

therefore, by using above information. we can conclude that :

\qquad \sf  \dashrightarrow \:  \angle1 \cong \angle3

7 0
2 years ago
Sean b= 5,79; c= 10,4,el angulo A= 54,46°, el angulo C mide ?
Rzqust [24]

Answer:

C \approx 91.732^{\circ}

Step-by-step explanation:

(This exercise is presented in Spanish and for that reason explanation will be held in such language)

El lado restante se determina por la Ley del Coseno:

a = \sqrt{b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A}

a = \sqrt{5.79^{2}+10.4^{2}-2\cdot (5.79)\cdot (10.4)\cdot \cos 54.46^{\circ}}

a \approx 8.466

Finalmente, el angulo C se halla por medio de la misma ley:

\cos C = - \frac{c^{2}-a^{2}-b^{2}}{2\cdot a \cdot b}

\cos C = -\frac{10.4^{2}-8.466^{2}-5.79^{2}}{2\cdot (8.466)\cdot (5.79)}

\cos C = -0.030

C \approx 91.732^{\circ}

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3 years ago
A number is multiplied by 5,and then 3 is subtracted from the product.the result is 12.find the number
Allushta [10]
The number is 3. The math is 5 x 3 = 15 15 - 3 = 12
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2 years ago
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