Your answer:
<span>Equation:
x(x+1) = 2(x+1)+77
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x^2+x = 2x+79
x^2-x-79 = 0
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This quadratic does not have an integer solution.</span>
The sum stays the same??? I’m pretty sure that’s the answer
When you multiply powers, they add, and when you divide them they subtract.
So I would first add the 2^a + 2^b +2^c to get 2^(a+b+c)
Then, divide by 2^(a+b). Because when you divide powers they subtract, you will be taking away the (a+b) from the (a+b+c) and you will be left with c on its own.
The answer is 2^c
Answer:
20-x; -20+x; -20-x; 20+x
Step-by-step explanation:
|14-x+6|
|20-x|
20-x; -20+x; -20-x; 20+x
