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soldi70 [24.7K]
2 years ago
7

Meridith runs at a rate of 190 meters per minute. use the formula d= r times t to find how far she runs in 6 minutes.

Mathematics
1 answer:
Mariulka [41]2 years ago
6 0
D= r×t
D= 190×6
D= 1140 meters
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Can somebody plz help answer both word problems correctly thanks! And show the steps on how u got the answer for both question :
Greeley [361]

Answer:

1. 24th 2. 140

Step-by-step explanation:

1. To figure out this problem, you would have to list the multiples of both 6 and 8.  

6 (6, 12, 18, 24)

8 (8, 16, 24) because both have 24, that would be the answer.

2. There are 8 windows, all with the same perimeter. Each window's perimeter is 17.5 (17 1/2) so 8 windows would be 140 ft. (17.50 x 8 = 140)

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Floyd is an aspiring music artist. He has a record contract that pays him a base rate of $200 a month and an additional $12 for
Roman55 [17]

Answer:

200 + 12n = 644  Answer: 37

Step-by-step explanation:

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3 years ago
A recipe for sparkling water juice calls for 1 1/2 quarts of sparkling water and 3/4 quart of grape juice
Alexxx [7]

Answer:

You would need 18 quarts of sparkling water to mix with 9 quarts of grape juice

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1 1/2 ---------> 3/4

x --------------> 9

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x = ((9) * (4/3)) * (1 1/2)

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7 0
2 years ago
Jack had 3 bags of golf balls with b balls in each bag; then his friend gave him 6 more golf balls. How many golf balls does Jac
earnstyle [38]
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3 0
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Read 2 more answers
X²+y²-6x+14y-1=0<br> and please show your work so I can learn
Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

x^2 + y^2 -6x+14y-1=0

We need to use the Quadratic Formula*

x =\frac{-b+\sqrt{b^2}-4ac }{2a} , \frac{-b-\sqrt{b^2} -4ac }{2a}

Thus, given the problem:

a = 1, b=-6, c=y^2+14y-1

So now we just need to plug them in the Quadratic Formula*

x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2} , x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}

As you can see, it is a mess right now. Therefore, we need to simplify it

x=\frac{6+2\sqrt{10-y^2-14y} }{2}, x = \frac{6-2\sqrt{10-y^2-14y} }{2}

Now that's get us to the final solution:

x=3+\sqrt{10-y^2-14y}, x=3-\sqrt{10-y^2-14y}

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

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2 years ago
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