Find the vertex of the function y = (1/5)x^2 + (4/5)X + 1/5
1 answer:
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<h2>Good evening ,</h2>
<em><u>Answer</u></em>:
q=-10
<em><u>Step-by-step explanation:</u></em>
D:y=-3x+q
let’s find q
A(-4,2)∈D ⇔ 2=-3(-4)+q ⇔ q=-10
then D:y=-3x-10
look at the photo for more details.
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