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marishachu [46]
3 years ago
5

Kyle volunteered 5.5 hours at the library this week. He needs to volunteer a total of 12 hours. Which equation can be used to fi

nd the number of hours, h, Kyle still needs to volunteer this week?
Mathematics
2 answers:
bonufazy [111]3 years ago
5 0

Answer:

12-5.5=h

12-5.5=6.5

Kyle needs to volunteer 6.5 more hours.

Step-by-step explanation:

Citrus2011 [14]3 years ago
4 0

Answer:

5.5 + h = 12

Step-by-step explanation:

Here, h represents the number of hours, Kyle still needs to volunteer this week,

Given,

He volunteered 5.5 hours at the library this week.

Since, the total number of hours he needs to volunteer = 5.5 + h

According to the question,

5.5 + h = 12

Which is the required equation.

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A line is represented by the equation 2x + 3y = 15. What is another way to represent the same line, for solving Y ? Help is need
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The another way to represent the same line, for solving y will be:  y= 5-\frac{2}{3}x

<u><em>Explanation</em></u>

Given equation of the line is:  2x+3y=15

"Solving y" means <u>we need to get</u> y <u>alone in left side.</u> So, we will eliminate all other terms except y from the left side.

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2x+3y-2x=15-2x\\ \\ 3y=15-2x

Now, we will <u>divide both sides by 3</u> for getting y alone. So.....

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3 years ago
Eighty percent of the light aircraft that disappear while in flight in a certain country are subsequently discovered. Of the air
gladu [14]

Answer:

a) P(B'|A) = 0.042

b) P(B|A') = 0.625

Step-by-step explanation:

Given that:

80% of the light aircraft that disappear while in flight in a certain country are subsequently discovered

Of the aircraft that are discovered, 63% have an emergency locator,

whereas 89% of the aircraft not discovered do not have such a locator.

From the given information; it is suitable we define the events in order to calculate the probabilities.

So, Let :

A = Locator

B = Discovered

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B' = No Discovered

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P(B') = 0.2

P(A|B) = 0.63

P(A'|B) = 1 - P(A|B)

P(A'|B) = 1- 0.63

P(A'|B) = 0.37

P(A'|B') = 0.89

P(A|B') = 1 - P(A'|B')

P(A|B') = 1 - 0.89

P(A|B') = 0.11

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P(B ∩ A) = P(A|B) P(B)

P(B ∩ A) = 0.63 × 0.8

P(B ∩ A) = 0.504

P(B ∩ A') =  P(A'|B) P(B)

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P(A') = 1 - 0.526

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P(B'|A) =  P(B' ∩ A)/P(A)

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(b) If it does not have an emergency locator, what is the probability that it will be discovered?

The probability that it will be discovered given that it does not have an emergency locator is:

P(B|A') = P(B ∩ A')/P(A')

P(B|A') = 0.296/0.474

P(B|A') = 0.625

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