Corey bought 2 1/2 liters of paint for $ 60. What was the cost per liter of paint?

Mathematics

2 answers:

Gnom [1K]2 years ago

7 0

It would be 24$ per liter

seropon [69]2 years ago

4 0

It costs $24 per liter.

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Jenny drives from Paris to Rochefort, a distance of 483 km. her average speed on the journey is 84 km/h, she leaves at 9:50. Wha

Mrrafil [7]

The correct answer is 3: 35

Explanation:

To calculate at what time Jenny will arrive in Rochefort, the first step is to calculate the approximate time of the trip. Now, to calculate this consider the time of a movement (t) equals to the distance (d) divided by the speed (s), the process is shown below:

t = 483 km / 84 km/h

t = 5.75 hours

In this number 5 refers to the hours and 0.75 represents 45 minutes considering 0.75 x 60 minutes in one hour = 45 minutes. Therefore, the total time from Paris to Rochefort is 5 hours and 45 minutes. Now, to calculate the time of arrival add this result to the time of departure.

Add the hours: 5 hours + 9 hours: 14 hours

Add the minutes: 50 minutes + 45 minutes =95 minutes

95 minutes are equivalent to 1 hour (60) minutes and 35 minutes

Calculate the total

Hours: 14 hours + 1 hour = 15 hours or 3 in the 12 hour system (15 hours - 12 hours = 3 p.m.)

Minutes: 35 minutes

4 0

3 years ago

Nola hiked down a trail at a steady rate for 10 minutes. Her change in elevation was −160 feet. Then she continued to hike down

RoseWind [281]

Ok so first, you need to figure out the change in elevation for each after one min. so we will write it as a ratio

10:-160 20:-300
So for the 10 min one, we will divide both sides by 10
1:-16 So the change in elevation per min. is -16
Now for the 20 one, we will divide by 20.
1: -15 So the change in elevation per min. is 15

So, the 10 min section of the walk the change of elevation was greater. Hope that helps! if you need me to explain something just ask!
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3 years ago

WILL MAKE BRAINLIEST!!! A triangular section of a lawn will be converted to river rock instead of grass. Maurice insists that th

Dvinal [7]

Let's consider the triangle ABC shown in the first diagram below. We name the sides with small letters: a, b, and c. We name the angles by the capital letters A, B, and C. Side a pairs with angle A° which are opposite each other. The same with side b and angle B° and side c and angle C°.

We can use the cosine rule when we know the length of two sides and the angle opposite the side that is unknown. For example, referring to the second diagram, we know the length of side a and side b and we are looking for the length of side c. We also know the angle that is located on the opposite of side c, then to solve this we can use the cosine rule

c² = a² + b² - 2ab(cos(C°))

The third diagram shows a scenario when sine rule can be used. Say we need the length of the side c. We know the length of side a, the size of angle A° and angle C° then we can use the sine rule

$\frac{c}{sin(C)} = \frac{a}{sin(A)}$

We can also use sine rule if we know length of side b and the size of angle B° instead of side a and angle A°