Hello,
Height: y
Number of branches: B=y-3
Number of leaves on one branche:n=10B²-B
Number of leaves on the tree:
nb=n*B=(10B²-B)*B=10B^3-B²
=10(y-3)^3-(y-3)²=(y-3)²[10(y-3)-1]=(y-3)²(10y-31)
a) if y=9 then nb=(9-3)²*(10*9-31)=36*59=2124.
Answer:
If solved by using quadratic formula, you would need to solve the rational equation by combining expressions and isolating the variable y
.
y
≈
2.45043159
Step-by-step explanation:
Answer:
∠H = 120
Step-by-step explanation:
See the attached figure
HALT is a parallelogram
So, angles H and T are supplementary.
∠H = 2x + 60 and ∠T = x + 30
∠H + ∠T = 180
∴ 2x + 60 + x + 30 = 180
∴ 3x + 90 = 180
∴ 3x = 180 - 90 = 90
∴ x = 90/3 = 30
So, ∠H = 2x + 60 = 2 * 30 + 60 = 60 + 60 = 120
Answer:
whats the q
Step-by-step explanation: