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Komok [63]
3 years ago
9

Tracy packages snack mix at a grocery store. She uses 1/5 of her supply of peanuts to make a trail mix and 3/5

Mathematics
1 answer:
Usimov [2.4K]3 years ago
5 0

Answer:

she'll use in total 1/5 + 3/5 = 4/5 from her 16 pounds of peanuts so 4/5 * 16 = 12.8

Not entirely sure about my answer

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Alex73 [517]
Hello answer is "n is more than 9" !
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3 years ago
Relative frequency of 80
aleksklad [387]

Answer:8/10

Step-by-step explanation:

7 0
2 years ago
the price of a taxi ride in phoenix includes an initial fee of $2.75 plus $2.20 per mile. write an equation to show the total pr
ki77a [65]
The format is y = mx + b
where y would be your C
x would be your M
m would be the price per mile (2.20)
and b would be your initial fee (2.75)

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4 0
3 years ago
A foresting service conducted a survey to see if tree farms that planted hardwood trees were more profitable over a 30-year peri
Advocard [28]

Answer:

The results are statistically significant because planting hardwood trees have a higher profit per acre.

Step-by-step explanation:

From the question above,

It shows that hardwood trees had a 46% higher Profit per acre than softwood trees.

Meaning that for every $100 made on softwood trees, $146 profit would be made on hardwood trees i(including both primary and secondary expenses; making the hardwood trees more profitable.

The information given is enough to reach a conclusion that planting hardwood trees have a higher profit per acre than softwood trees.

8 0
3 years ago
Which of the equations below could be the equation of this parabola?
nirvana33 [79]

Answer:

 y=-4x^2  is the equation of this parabola.

Step-by-step explanation:

Let us consider the equation

y=-4x^2

\mathrm{Domain\:of\:}\:-4x^2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:-4x^2:\quad \mathrm{X\:Intercepts}:\:\left(0,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)

As

\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=a\left(x-m\right)\left(x-n\right)

\mathrm{is\:the\:average\:of\:the\:zeros}\:x_v=\frac{m+n}{2}

y=-4x^2

\mathrm{The\:parabola\:params\:are:}

a=-4,\:m=0,\:n=0

x_v=\frac{m+n}{2}

x_v=\frac{0+0}{2}

x_v=0

\mathrm{Plug\:in}\:\:x_v=0\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}

y_v=-4\cdot \:0^2

y_v=0

Therefore, the parabola vertex is

\left(0,\:0\right)

\mathrm{If}\:a

\mathrm{If}\:a>0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}

a=-4

\mathrm{Maximum}\space\left(0,\:0\right)

so,

\mathrm{Vertex\:of}\:-4x^2:\quad \mathrm{Maximum}\space\left(0,\:0\right)

Therefore,  y=-4x^2  is the equation of this parabola. The graph is also attached.

7 0
3 years ago
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