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disa [49]
3 years ago
10

The type of triangle formed by joining the points (7,10), (-2 ,5) and (3, -4)

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0
A scalene triangle is formed from the three points.
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The value of y is two less than four times the value of x
Archy [21]

Answer:

Step-by-step explanation:

four times the value of x = 4*x = 4x

two less than four times the value of x = 4x - 2

y= 4x - 2

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4 years ago
The segment joining the two legs of a trapezoid is called
mel-nik [20]

Answer:

Base

Step-by-step explanation:

The segment joining the two legs of a trapezoid is called base

7 0
3 years ago
Read 2 more answers
Please solve this please​
ale4655 [162]

Answer:

C) \frac{2z+15}{6x-12y}

E) \frac{7d+5}{15d^2+14d+3}

F) \frac{-7a-b}{6b-4a}

Step-by-step explanation:

C)

One is given the following equation

\frac{z+1}{x-2y}-\frac{2z-3}{2x-4y}+\frac{z}{3x-6y}

In order to simplify fractions, one must convert the fractions to a common denominator. The common denominator is the least common multiple between the given denominators. Please note that the denominator is the number under the fraction bar of a fraction. In this case, the least common multiple of the denominators is (6x-12y). Multiply the numerator and denominator of each fraction by the respective value in order to convert the fraction's denominator to the least common multiple,

\frac{z+1}{x-2y}-\frac{2z-3}{2x-4y}+\frac{z}{3x-6y}

\frac{z+1}{x-2y}*\frac{6}{6}-\frac{2z-3}{2x-4y}*\frac{3}{3}+\frac{z}{3x-6y}*\frac{2}{2}

Simplify,

\frac{z+1}{x-2y}*\frac{6}{6}-\frac{2z-3}{2x-4y}*\frac{3}{3}+\frac{z}{3x-6y}*\frac{2}{2}

\frac{6z+6}{6x-12y}-\frac{6z-9}{6x-12y}+\frac{2z}{6x-12y}

\frac{(6z+6)-(6z-9)+(2z)}{6x-12y}

\frac{6z+6-6z+9+2z}{6x-12y}

\frac{2z+15}{6x-12y}

E)

In this case, one is given the problem that is as follows:

\frac{2}{3d+1}-\frac{1}{5d+3}

Use a similar strategy to solve this problem as used in part (c). Please note that in this case, the least common multiple of the two denominators is the product of the two denominators. In other words, the following value: ((3d+1)(5d+3))

\frac{2}{3d+1}-\frac{1}{5d+3}

\frac{2}{3d+1}*\frac{5d+3}{5d+3}-\frac{1}{5d+3}*\frac{3d+1}{3d+1}

Simplify,

\frac{2}{3d+1}*\frac{5d+3}{5d+3}-\frac{1}{5d+3}*\frac{3d+1}{3d+1}

\frac{2(5d+3)}{(3d+1)(5d+3)}-\frac{1(3d+1)}{(5d+3)(3d+1)}

\frac{10d+6}{(3d+1)(5d+3)}-\frac{3d+1}{(5d+3)(3d+1)}

\frac{(10d+6)-(3d+1)}{(3d+1)(5d+3)}

\frac{10d+6-3d-1}{(3d+1)(5d+3)}

\frac{7d+5}{(3d+1)(5d+3)}

\frac{7d+5}{15d^2+14d+3}

F)

The final problem one is given is the following:

\frac{3a}{2a-3b}-\frac{a+b}{6b-4a}

For this problem, one can use the same strategy to solve it as used in parts (c) and (e). The least common multiple of the two denominators is (6b-4a). Multiply the first fraction by a certain value to attain this denomaintor,

\frac{3a}{2a-3b}-\frac{a+b}{6b-4a}

\frac{3a}{2a-3b}*\frac{-2}{-2}-\frac{a+b}{6b-4a}

Simplify,

\frac{3a}{2a-3b}*\frac{-2}{-2}-\frac{a+b}{6b-4a}

\frac{-6a}{6b-4a}-\frac{a+b}{6b-4a}

\frac{(-6a)-(a+b)}{6b-4a}

\frac{-6a-a-b}{6b-4a}

\frac{-7a-b}{6b-4a}

4 0
3 years ago
You are single and claim 1 allowance. You presently earn $520.00
Rzqust [24]
I’m 644.001 dollars if not I’m sorry
6 0
4 years ago
Which account option is more convenient for frequent check or debit card withdrawals and purchases but gains no interest?
olya-2409 [2.1K]

The best account if one plans to make frequent withdrawals via check or debit card is A<u>. Checking account </u>

Checking accounts:

  • Are the least interest bearing accounts
  • Allow for frequent withdrawals using a check or debt card
  • Charge lower fees

Checking accounts are best when a person wants easy access to their money because they can get to it via checks or debit cards. The drawback however, is that interest on these accounts are low.

In conclusion, option A is correct.

<em />

<em>Find out more about </em><em>checking accounts </em><em>at brainly.com/question/21714367. </em>

7 0
3 years ago
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