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2 years ago

15

The length of a field, 1.2 km long is represented on a map by a line 40mm long. What is the scale of the map

1 answer:

Katarina [22]2 years ago

6 0

Answer:

33 1/3 mm = 1 km, or 33.33 to 1

Step-by-step explanation:

40/1.2=33 1/3

I think

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What is the range for this set of data? 7, 15, 12Mrs. Juarez graded ten English papers and recorded the scores. 92, 95, 100, 62,

ra1l [238]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the complete question in the attached file.

Arrange the value into the ascending order:

$62, 88, 89, 90, 92, 95, 96, 98, 100, 100$

Calculating the Range:

$= Greatest - Lowest\\\\= 100 - 62\\\\ = 38$

Outlier = This might be the value "far" from other data values= 62

The range of scores would be, sans outlier,

$88, 89, 90, 92, 95, 96, 98, 100, 100$

Calculating the range without outlier $= 100 - 88 = 12$

Inter Quartile Range $= Q_3 - Q_1$

$IQR = 98 - 89 = 11$

Calculating the IQR without outlier $= 99 - 89.5 = 9.5$

Therefore,

Option a is "True".

Option b is "True".

Option c is "True".

Option d is "False".

Option e is "False".

Option f is "True".

5 0

2 years ago

Jason had to replace the floor of a triangular portion of his dining room. The portion had a height that was twice as high as th

Eva8 [605]

Answer:

4 feet

Step-by-step explanation:

We know the the area of a triangle can be represented as $\frac{bh}{2}$ .

Since the height is twice the base, we can substitute the value $2b$ in as $h$ in the expression, making it $\frac{b\cdot2b}{2}$ . If the area is 16, we can make the equation

$\frac{b\cdot2b}{2} = 16$

Now to solve for b.

$\frac{2b^2}{2} = 16\\\frac{2b^2}{2}\cdot2 = 16\cdot2\\\\2b^2 = 32\\\\2b^2\div2 = 32\div2\\\\b^2 = 16\\\\b=4$

Hope this helped!

3 0

3 years ago

Alex has 7 pounds of birdseed and 5 bird feeders.

hram777 [196]

Well, we dont know because we cant see the barmodels

5 0

2 years ago

Find all solutions of the equation algebraically. Use a graphing utility to verify the solutions graphically. (Enter your answer

Anuta_ua [19.1K]

Answer:

The solutions of the equation are 0 and 0.75.

Step-by-step explanation:

Given : Equation $16x^4 - 24x^3 +9x^2 =0$

To find : All solutions of the equation algebraically. Use a graphing utility to verify the solutions graphically ?

Solution :

Equation $16x^4 - 24x^3 +9x^2 =0$

$x^2(16x^2-24x+9)=0$

Either $x^2=0$ or $16x^2-24x+9=0$

When $x^2=0$

$x=0$

When $16x^2-24x+9=0$

Solve by quadratic formula, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-24)\pm\sqrt{(-24)^2-4(16)(9)}}{2(16)}$

$x=\frac{24\pm\sqrt{0}}{32}$

$x=\frac{24}{32}$

$x=\frac{3}{4}$

$x=0.75$

The solutions of the equation are 0 and 0.75.

For verification,

In the graph where the curve cut x-axis is the solution of the equation.

Refer the attached figure below.

7 0

3 years ago

For the following right triangle, find the side length x. Round your answer to the nearest hundredth.

atroni [7]

Answer:

14.97

Step-by-step explanation:

8 0

2 years ago