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lilavasa [31]
2 years ago
5

Quadrilateral with vertices at A(2,2), B(1,5) C(5,3), D(4,6)

Mathematics
1 answer:
MatroZZZ [7]2 years ago
6 0
I have attached an image explaining how to solve this problem.
(“m” means slope)

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Which angles are corresponding angles
a_sh-v [17]

Answer:

second option is correct onee

Step-by-step explanation:

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8 0
2 years ago
Find the discriminant for each quadratic function below. Then list the number of zeros/solutions for each quadratic function.
Hunter-Best [27]

Answer:

Step-by-step explanation:

The discriminant is found in

b^2-4ac which is part of the quadratic formula. In

4x^2+10x-16=0, a = 4, b = 10, c = -16. Filling in for the discriminant:

10^2-4(4)(-16)=100+256=356

It's positive so we know we have real roots; it's not a perfect square, so our solutions are 2 complex rational.

In -16x^2-7x+3=0, a = -16, b = -7, c = 3. Filling in for the discriminant:

(-7)^2-4(-16)(3)=49+192=241

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5 0
3 years ago
Graph this function using intercepts Solve 10x+9y=-90
Alex17521 [72]

Answer:

Step-by-step explanation:

So first, lets solve for the intercepts.

Let’s start by finding the x intercept.

Plug in 0 for y.

10x+9(0)=-90

10x=-90

X=-9, so your first point on your line will be (-9,0).

Now the y intercept.

Plug in 0 for x.

10(0)+9y=-90

9y=-90

Y=-10, so your second point on your line will be (0,-10).

Use those points to create your line.

6 0
3 years ago
Issss thissss correct?
alexdok [17]
Yes, your answer is correct
5 0
3 years ago
Solve the following equations: 5y/(1 1/3) = y−0.9/0.2
sergejj [24]
The answer is y= -1.63
7 0
3 years ago
Read 2 more answers
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