The answer to your question is 8.1
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Answer:
1,350 cm^2
Step-by-step explanation:
It's a cube so all faces/bases are the same.
15 × 15 = 225
225 × 6 = 1,350
2x-4
If x is the amount the other team scored then the 2x is double. This gives that 4 less than double the amount of the other team would be minus 4
