The inequality that describes this graph of the number line is x ≥ 4
<h3>How to determine the inequality that describes this graph?</h3>
From the question, we have the following properties:
- The graph is a number line
- The number line extends at both ends
- The number line starts from less than -5 and ends at greater than 5
- There is a heavy arrow that extends from a circle over positive 4 to the right.
The property 3 above implies that the domain of the number line is the set of all real numbers.
The property 4 above implies that the inequality of the number line is a greater than or equal to inequality, and the value starts from 4
This is represented by the following inequality
x ≥ 4
Hence, the inequality that describes this graph of the number line is x ≥ 4
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Answer:
I think it is 52 degrease
Step-by-step explanation:
I think it’s p=36 because you have to do the opposite on both sides..
So..
q=-12
P/-12=-3
+12 *12
P=36
Answer:
Step-by-step explanation:
0.75 is equivalent to three quarters, or (3/4).
3/4 would be the fraction. -37 would be the whole number.
Hope this helps.
1 In general, given
a
x
2
+
b
x
+
c
ax
2
+bx+c, the factored form is:
a
(
x
−
−
b
+
b
2
−
4
a
c
2
a
)
(
x
−
−
b
−
b
2
−
4
a
c
2
a
)
a(x−
2a
−b+
b
2
−4ac
)(x−
2a
−b−
b
2
−4ac
)
2 In this case,
a
=
3
a=3,
b
=
−
54
b=−54 and
c
=
343
c=343.
3
(
y
−
54
+
(
−
54
)
2
−
4
×
3
×
343
2
×
3
)
(
y
−
54
−
(
−
54
)
2
−
4
×
3
×
343
2
×
3
)
3(y−
2×3
54+
(−54)
2
−4×3×343
)(y−
2×3
54−
(−54)
2
−4×3×343
)
3 Simplify.
3
(
y
−
54
+
20
3
ı
6
)
(
y
−
54
−
20
3
ı
6
)
3(y−
6
54+20
3
)(y−
6
54−20
3
)
4 Factor out the common term
2
2.
3
(
y
−
2
(
27
+
10
3
ı
)
6
)
(
y
−
54
−
20
3
ı
6
)
3(y−
6
2(27+10
3
)
)(y−
6
54−20
3
)
5 Simplify
2
(
27
+
10
3
ı
)
6
6
2(27+10
3
)
to
27
+
10
3
ı
3
3
27+10
3
.
3
(
y
−
27
+
10
3
ı
3
)
(
y
−
54
−
20
3
ı
6
)
3(y−
3
27+10
3
)(y−
6
54−20
3
)
6 Factor out the common term
2
2.
3
(
y
−
27
+
10
3
ı
3
)
(
y
−
2
(
27
−
10
3
ı
)
6
)
3(y−
3
27+10
3
)(y−
6
2(27−10
3
)
)
7 Simplify
2
(
27
−
10
3
ı
)
6
6
2(27−10
3
)
to
27
−
10
3
ı
3
3
27−10
3
.
3
(
y
−
27
+
10
3
ı
3
)
(
y
−
27
−
10
3
ı
3
)
3(y−
3
27+10
3
)(y−
3
27−10
3
I hope this help you
