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My name is Ann [436]
3 years ago
10

Anyone wanna help a girl out w some pre-cal? The range & one to one function is hard for me w this graph. I don’t understand

the 3 different line plots on it.

Mathematics
1 answer:
mario62 [17]3 years ago
6 0

"One-to-one" here implies that no particular y-value occurs more than once. Looking at the sloping part of the shown function, we see that this is the case.  But not the horizontal parts of the graph, where y takes on one value multiple times (y=1 and y=4).

Apply the Horizontal Line Test.  If a horiz. line drawn thru the graph intersects the graph in more than one place, the function fails this Test and is not one-to-one.  So we conclude that the function shown is NOT one-to-one.

The range of this function is a list of all possible values that the function may take on.  From the graph it is evident that the smallest y-value is almot but not quite -2, and that the largest is 4.  Thus, the range is (-2,4).

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Select the correct answer.
kati45 [8]

Answer:

25

Step-by-step explanation:

divide 48 by 4 which is 25%

3 0
3 years ago
If 95 % of the students are present in a school and the number of absent students is 25, find the total number of students in th
Karolina [17]
100 minus 95 equals 5
25 equals 5%
100 divided by 5 equals 20
20 times 25 equals 500
500 minus 25 equals 475
Answer:475 students present/ 500 students total in school
8 0
3 years ago
A rectangle has length that is 5 less than 2 times the width. Write an expression for the area of the rectangle.
a_sh-v [17]

We are given a relationship between the sides of a rectangle, that is, the length of one of its sides is 5 less two times its width, and we are asked to find an expression for the area. Let's remember that the area of a rectangle is equal to the product of the length of its side by its width. Let "w" be the length of the rectangle and "L" its lenght, then the area is given by the following formula:

A=Lw

We can use the relationship given in the problem, that is, its length being five less two times its width, that is:

L=5-2w

Replacing in the formula for the area we get:

A=(5-2w)w

Now we use the distributive law:

A=5w-2w^2

7 0
8 months ago
Find n. Perimeter = 86 in.
FromTheMoon [43]
Let the length of rectangle be L and the width of rectangle be W.
Since length exceeds the width by 25 inches, length will be
L = W + 25

Now the perimeter, P, is given by
P = 2(L + W)
Substituting L = W + 25 in the above equation,
P = 2(W + 25 + W)
P = 2(2W + 25)
P = 4W + 50
But P = 86 inches
P = 4W + 50 = 86
4W = 86 - 50 = 36
W = 36/4 = 9

Hence, width W = 9 inches.
Length L = W + 25 = 9 + 25 = 34 inches.
5 0
3 years ago
The average load is $350. It comes with an average of 15%, which is compounded every two weeks. What is the average amount for a
morpeh [17]
I think it would be 26.25 if you multiply 350 by .15 and rdivide by two
7 0
3 years ago
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