Answer:
T₂ = 421.4 K
Step-by-step explanation:
The temperature, T, of a given mass of gas varies inversely with its Volume,V.
We have,
V₁ = 98 cm³, T₁ = 28° C = (28+273) K = 301 K
V₂ = 70 cm₃
We need to find the new temperature of the gas. Using the above relation to find T₂.
Hence, the required temperature of the gas is 421.4 K.
C(3,-4), r=4*sqrt(2)
C(p, q)
x^2+y^2+dx+ey+f=0
p=-d/2, q=-e/2, r^2=p^2+q^2-f
x^2+y^2 - 6x+8y-7=0
p=-(-6)/2=6/2=3
q=-8/2=-4
r^2=3^2 +(-4)^2+7
r^2=9+16+7
r^2=32
r=sqrt(32)
r=sqrt(16*2)
r=4*sqrt(2)
B
Step-by-step explanation: it is easy