Answer:
6 crackers, 9 marshmallows
Step-by-step explanation:
You have to divide to find how many graham crackers and marshmallows are needed to make 1 s'more:
8 / 4 = 2, so 2 crackers per s'more. Then,
12 / 4 = 3, so 3 marshmallows per s'more. Now that we know this, all we have to do is multiply each number by 3 to make 3 s'mores.
2 * 3 = 6, so 6 crackers, and
3 * 3 = 9, so 9 marshmallows.
:)
Answer:
Yes it does
Step-by-step explanation:
(125/35)=(25/7)
((125/5)/(35/5))=(25/7)
(25/7)=(25/7)
What do you need help with?
Answer:
I'm going to paint you a picture in words of what this looks like on paper. We have a train leaving from a point on your paper heading straight west. We have another train leaving from the same point on your paper heading straight east. This is the "opposite directions" that your problem gives you.
Now let's make a table:
distance = rate * time
Train 1
Train 2
We will fill in this table from the info in the problem then refer back to our drawing. It says that one train is traveling 12 mph faster than the other train. We don't know how fast "the other train" is going, so let's call that rate r. If the first train is travelin 12 mph faster, that rate is r + 12. Let's put that into the table
distance = rate * time
Train 1 r
Train 2 (r + 12)
Then it says "after 2 hours", so the time for both trains is 2 hours:
distance = rate * time
Train 1 r * 2
Train 2 (r + 12) * 2
Since distance = rate * time, the distance (or length of the arrow pointing straight west) for Train 1 is 2r. The distance (or length of the arrow pointing straight east) for Train 2 is 2(r + 12) which is 2r + 24. The distance between them (which is also the length of the whole entire arrow) is 232. Thus:
2r + 2r + 24 = 232 and
4r = 208 so
r = 52
This means that Train 1 is traveling 52 mph and Train 2 is traveling 12 miles per hour faster than that at 64 mph
Step-by-step explanation:
Answer:
g(-2) = -6
g(0) = 0
g(5) = 15
Step-by-step explanation:
For each of the evaluations, you have to plug in the number everywhere where there is an x
