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Amanda [17]
3 years ago
6

Does "........." at the end of a number mean that it is a pattern and it repeats or does it mean it is an irrational number (doe

sn't terminate or repeat).
Mathematics
2 answers:
natka813 [3]3 years ago
5 0
It means that it does not repeat, this is typically found in a sequence, which will be elaborated in Algebra 2 which you will most likely take in junior year of high school
REY [17]3 years ago
4 0
I believe it means that it is a pattern
You might be interested in
A) The equilibrium prices P1 and P2 for two goods satisfy the equations:
Allisa [31]

The value of P1 and P2 using the inverse matrix is 5 and 6 respectively.

<h3 />

The equilibrium prices of the three independent commodities using the inverse matrix are P1 = 4, P2 = 7, P3 = 8 respectively.

<h3>What is a matrix?</h3>

A matrix can be defined as a collection of integers(numbers that are either positive or negative) that are organized in rows and columns to construct a rectangular array. The numbers in this matrix system are referred to as elements.

To determine the values of P1 and P2 for the system of equations given by using an inverse matrix, we have:

a)

9P1 + P2 = 51

3P1 +4P2 = 39

Representing the above data in matrix form, we have:

\left[\begin{array}{cc}9&1\\3&4\\ \end{array}\right] \left[\begin{array}{c} \mathbf{P_1} \\ \mathbf{P_2}\\ \end{array}\right] =  \left[\begin{array}{c} \mathbf{51} \\ \mathbf{39} \\ \end{array}\right] which is in the form AX = B

  • In order for us to determine the values of P1 and P2, Let take the inverse of A⁻¹ on both sides of the AX= B, we have:

\mathbf{{A^{-1} AX} = A^{-1} B}

X = A⁻¹ B

Let's start by finding A⁻¹;

\mathbf{A = \left[\begin{array}{cc}9&1\\3&4\end{array}\right] }

\mathbf{A^{-1} = \dfrac{1}{36-3}\left[\begin{array}{cc}4&-1\\3&9\end{array}\right] }

\mathbf{A^{-1} = \dfrac{1}{33}\left[\begin{array}{cc}4&-1\\3&9\end{array}\right] }

Now, Let's Find A⁻¹B;

\mathbf{A^{-1}B = \dfrac{1}{33}\left[\begin{array}{cc}4&-1\\3&9\end{array}\right] \left[\begin{array}{c}51\\39\\ \end{array}\right] }

\mathbf{\implies \dfrac{1}{33}\left[\begin{array}{cc}204&-39\\-153&+351\end{array}\right]  }

\mathbf{\implies \left[\begin{array}{c}\dfrac{165}{33}\\ \\ \dfrac{198}{33}\end{array}\right]  }

\mathbf{\implies \left[\begin{array}{c}5\\ \\ 6\end{array}\right]  }

\left[\begin{array}{c}\mathbf{P_1}\\  \mathbf{P_2}\end{array}\right]= \left[\begin{array}{c}5\\ 6 \end{array}\right] }

Therefore, we can conclude that the value of P1 and P2 using the inverse matrix is 5 and 6 respectively.

b)

To determine the equilibrium prices of the three independent commodities using the inverse matrix, we have:

P₁ + 2P₂ + 3P₃ = 42

2P₁ + P₂ + 4P₃ = 47

P₁ + 3P₂ + 4P₃ = 57

The matrix in AX = B form is computed as:

\implies\left[ \begin{array}{ccc}1&2&3\\2&1&4\\1&3&4\end{array}\right] \left[\begin{array}{c}P_1\\P_2\\P_3  \end{array}\right] = \left[\begin{array}{c}42\\47\\ 57\end{array}\right]

\mathbf{A^{-1} = \dfrac{1}{|A|} \  (adj \  A)}

\mathbf{A^{-1} = \dfrac{1}{1(4-12) -2(8-4) +3(6-1)} \left[\begin{array}{ccc}-8&4&5\\1&1&-1\\5&2&-3\end{array}\right] }^1

\mathbf{A^{-1}B = -1 \left[\begin{array}{ccc}-8&1&5\\-4&1&2\\5&2&-3\end{array}\right] }\left[\begin{array}{c}42\\47\\57\end{array}\right]

\mathbf{A^{-1}B = -\left[\begin{array}{ccc}-336&+47&+285\\-168&+47&+114\\210&-47&-171\end{array}\right] }

\mathbf{A^{-1}B = -\left[\begin{array}{c}-4\\-7\\-8\end{array}\right] }

\mathbf{A^{-1}B = \left[\begin{array}{c}4\\7\\8\end{array}\right] }

Therefore, we can conclude that the values of P1 = 4, P2 = 7, P3 = 8 respectively.

Learn more about matrix here:

brainly.com/question/1821869

3 0
2 years ago
Simplify 2a + 6b - 3(4a - b)
Dmitry [639]

Answer:

Answer: -10a+9b (I think)

7 0
3 years ago
Read 2 more answers
HELP ASAP I WILL GIVE BRAINLEST
insens350 [35]

Answer:

wheres the question?

Step-by-step explanation:

have a nice day and stay safe:)

7 0
3 years ago
While practicing her foul kicks for soccer, Louisa made 85% of her shots. If she made 51 shots, how many shots did she kick in t
vesna_86 [32]

Answer:

the exact answer is 58.65

Step-by-step explanation:

since she made 85% of her shots, that means in total from her 51 shots, she made 115% more than 51 (you add 15% to 100%). The 15% is from the difference of 100% and 85%. You then change 115% to fraction form (1.15) and multiply it by the amount of shots made, getting you 58.65. Since you can't make a fraction in terms of a real life scenario like this, you prob need to round or something. Diff teachers want diff things

3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B%5Csqrt%7B13%7D%7D" id="TexFormula1" title="\frac{4}{\sqrt{13}}" alt="\frac{4
mafiozo [28]

Answer:

\frac{4}{ \sqrt{13} }  \times  \frac{ \sqrt{13} }{ \sqrt{13} }  =  \frac{4 \sqrt{13} }{13}

I hope I helped you^_^

5 0
3 years ago
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