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Oliga [24]
3 years ago
12

}{\sqrt{13}}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
mafiozo [28]3 years ago
5 0

Answer:

\frac{4}{ \sqrt{13} }  \times  \frac{ \sqrt{13} }{ \sqrt{13} }  =  \frac{4 \sqrt{13} }{13}

I hope I helped you^_^

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Step-by-step explanation:

j×56

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3 years ago
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Help subtract (xsquared +43x10)-(10xsquared-5x+10 express the answer in standard form
ad-work [718]

Answer:

\large\boxed{(x^2+43x+10)-(10x^2-5x+10)=-9x^2+48x}

Step-by-step explanation:

(x^2+43x+10)-(10x^2-5x+10)\\\\=x^2+43x+10-10x^2-(-5x)-10\\\\=x^2+43x+10-10x^2+5x-10\qquad\text{combine like terms}\\\\=(x^2-10x^2)+(43x+5x)+(10-10)\\\\=-9x^2+48x

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4 years ago
What is the quotient StartFraction 15 p Superscript negative 4 Baseline q Superscript negative 6 Baseline Over negative 20 p Sup
zhannawk [14.2K]

Answer:

- \frac{3}{4} \times  \frac{p^{8} }{q^{3} }

Step-by-step explanation:

We have to find the quotient of the following division, \frac{15p^{-4}q^{-6} }{- 20p^{-12} q^{-3}}.

Now, \frac{15p^{-4}q^{-6} }{- 20p^{-12} q^{-3}}

= - \frac{3}{4} p^{[- 4 - (- 12)]} q^{[-6 - (- 3)]} {Since all the terms in the expression are in product form, so we can treat them separately}

{Since we know the property of exponent as \frac{a^{b} }{a^{c} } = a^{(b - c)}}

= - \frac{3}{4} p^{8} q^{-3}

= - \frac{3}{4} \times  \frac{p^{8} }{q^{3} } (Answer)

{Since we know, a^{-b} = \frac{1}{a^{b} }}

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Step-by-step explanation:

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natta225 [31]

2.8392222e+17

Step-by-step explanation:

283838383838382828 + 83838383888282=2.8392222e+17

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