Complete Question
Educational Television In a random sample of 200 people, 159 said that they watched educational television. Find the 90% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.
Answer:
The 90% confidence interval is
Step-by-step explanation:
From the question we are told that
The sample size is n = 200
The number of people that watched the educational television is 
Generally the sample proportion is mathematically represented as

=> 
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the margin of error is mathematically represented as
=>
=>
Generally 95% confidence interval is mathematically represented as
=>
=>
Answer:
1/4
Step-by-step explanation:
Answer:
63 degrees
Step-by-step explanation:
(180-54)/2=126/2=63
<u>x / 5 = y</u>
Multiply each side by 5 : x = 5y
Multiply each side by 2 : <em>2x = 10y</em>
IQR= Q3-Q1
Airport 1
Q3 is 8
Q1 is 2
8-2= 6
Airport 1 IQR is 6
Airport 2
Q3 is 8
Q1 is 3
8-3= 5
Airport 2 IQR Is 5