Question

A rocket was launched into the air from a platform above the ground.the height, in feet ,of the rocket above the ground t seconds after being thrown can be determined by -16t^2 64t 80 .what does the 80in this expression represent

Answer 1

The rocket was launched from a platform 80 ft above the ground.

Answer 2

Answer:

The rocket was launched from the platform which is 80 feet above the ground.

Step-by-step explanation:

We are given,

The function representing the height of the rocket launched from the platform after t seconds by,

$f(t)=-16t^2+64t+80$

Now, when t = 0, we get,

$f(0)=-16\times 0^2+64\times 0+80$ i.e. f(0)= 80

That is, the height of the rocket at t = 0 seconds is 80 feet.

Thus, 80 represents the height of the rocket above the ground.

Hence, the rocket was launched from the platform which is 80 feet above the ground.