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lutik1710 [3]
3 years ago
7

Define the random variables X and X in words. X is the amount of time an individual waits at the courthouse to be called for ser

vice. X is the mean wait time for a sample of individuals. X is the number of individuals at the courthouse to be called for service. X is the average number of individuals at the courthouse. X is the number of individuals at the courthouse to be called for service. X is the average number of individuals at the courthouse. X is the amount of time an individual waits at the courthouse to be called for service. X is the mean wait time for a sample of individuals.
Mathematics
1 answer:
densk [106]3 years ago
5 0

<u>Question</u>

Suppose that a committee is studying whether or not there is excessive time waste in our judicial system. It is interested in the mean amount of time individuals spend at the courthouse waiting to be called for jury duty. The committee randomly surveyed 81 people who recently served as jurors. The sample mean wait time was 4 hours with a sample standard deviation of 1.2 hours. Define the random variables X and \bar{X} in words.

Answer:

(B)

  • X is the amount of time an individual waits at the courthouse to be called for service.
  • \bar{X}  is the mean wait time for a sample of individuals.

Step-by-step explanation:

The random variable X is the amount of time for which each of the prospective juror waits at the courthouse before being called for service.

\bar{X}  is the mean wait time for a the given sample of individuals. In the case given,

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A factory whistle blows every 30 minutes. The clock tower chimes every 15 minutes. If they both sounded at 1:00 p.M.,at what tim
madam [21]

Answer:

1.30 p.M.

Step-by-step explanation:

The factory whistle blowed at 1:00 p.M, and it blows every 30 minutes, so it will blow again at 1:30 p.M.

The clock tower chimed at 1.00 p.M., and it chimes every 15 minutes, so it will chime again at 1:15 p.M, and after that, it will chime again at 1:30 p.M.

So, you will hear them both at the same time at 1:30 p.M.

We can also solve this problem using LCM:

the least commom multiple between 15 and 30 is 30, so we just need to sum 30 to the inicial time (1:00 p.M.), so the time they will "find each other" again is 1.30 p.M.

7 0
3 years ago
.…: need this answers.....
Leto [7]
Sorry, cannot just give you answers without your input.
I'd suggest that you look up online or in your textbook each of the items under "Type of Boundary."  The results you'd get will likely help you fill in the rest of the boxes.
3 0
3 years ago
Help me this is important
Karolina [17]
The third option is correct
7 0
3 years ago
Read 2 more answers
Pls help with question 5 i’ll be giving a brainliest
Klio2033 [76]

Answer:

Hello there!

The answer you are looking for is B.!

Step-by-step explanation:

That is the only one that makes sense.

Have a great day!

8 0
3 years ago
A rectangular plot of land that contains 1500 square meters will be fenced and divided into two equal portions by an additional
photoshop1234 [79]
Let the length be x and the width be w

The perimeter will be:
2x+3w=1500

thus
3w=(1500-2x)
w=(1500-2x)/3
w=500-2/3x

The area will be:
A=x*w
A=x(500-2/3x)
A=500x-(2/3)x²

The above is a quadratic equation; thus finding the axis of symmetry we will evaluate for the value of x that will give us maximum area.

Axis of symmetry:
x=-b/(2a)
from our equation:
a=(-2/3) and b=500
thus
x=-500/[2(-2/3)]
x=375
the length will be 375 m

The width will be 250 m

4 0
3 years ago
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