4. The temperature at 6:00 a.m. was 45°F and the temperature at 10:30 a.m. was 12.8°C. What was the change in temperature betwee
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X will be the speed of species b and 4x will be the speed of species a:
x + 4x = 180
5x = 180
x = 180 / 5
x = 36 m/h
If species b has a speed of 36 m/h, the speed of species a is 4 times that:
4 x 36 = 144 m/h.
Answer:
Hope it helped,
Happy homework/ study/ exam!
x + 4x = 180
5x = 180
x = 180 / 5
x = 36 m/h
If species b has a speed of 36 m/h, the speed of species a is 4 times that:
4 x 36 = 144 m/h.
Answer:
Hope it helped,
Happy homework/ study/ exam!