Answer:
units I THINK
Step-by-step explanation:
using the distance formula, -2 - 1 = -3
-3 x -3 = 9
-5 - 4 = -9 x -9 = 81
81 + 9 = 90
sqrt 90 simplified is .
so im pretty sure that's the answer.
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
Answer:
95 intervals
Step-by-step explanation:
Given that
population mean = 100
standard deviation = 15
number of interval that involve the mean for 95% confidence interval is calculated as
We know that when we measure the 99 percent confidence interval, 99 outof 100 confidence interval are required to provide the mean population.
similarly
Assuming we measure a confidence interval of 95 percent, then we should expect 95 out of 100 confidence interval to provide the mean population therefore, answer is 95
See it is < and not ≤ so we don't include -4
put a circle around -4 but don't shade it in
to get there, move 4 units left from 0
then we see x is less than -4
so shade to the left of the circle
